1 g of a non-volatile non-electrolyte solute is dissolved in 100 g of two different solvents A and B whose ebullioscopic constants are in the ratio of 1:5. The ratio of the elevation in their boiling

Question

1 g of a non-volatile non-electrolyte solute is dissolved in 100 g of two different solvents A and B whose ebullioscopic constants are in the ratio of 1:5. The ratio of the elevation in their boiling points, , is: (assuming they have the same molar mass)

Canvas Classes · Accepted Answer

Strategy:
 The elevation in boiling point () is proportional to the ebullioscopic constant () when the molality (moles of solute per kg of solvent) is constant.

Step 1: Confirm same molality ()
- Mass of solute = 1 g (for both).
- Molar mass  = same (for both).
- Mass of solvent = 100 g (for both).
Since all mass components are identical, both solutions have the same molality .

Step 2: Relate elevation to the constants

Given the ratio of constants is , the ratio of elevations is also .

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