A solution is prepared by dissolving 0.6 g of urea (molar mass = 60 g mol⁻¹) and 1.8 g of glucose (molar mass = 180 g mol⁻¹) in 100 mL of water at 27°C. The osmotic pressure of the solution is:

()

Question

A solution is prepared by dissolving 0.6 g of urea (molar mass = 60 g mol⁻¹) and 1.8 g of glucose (molar mass = 180 g mol⁻¹) in 100 mL of water at 27°C. The osmotic pressure of the solution is:

()

Canvas Classes · Accepted Answer

Strategy:
 For a mixture of non-volatile, non-electrolytic solutes, the total osmotic pressure is the sum of the partial pressures, which corresponds to the total molarity of particles ().

Step 1: Calculate moles for each component
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Step 2: Calculate total molarity ()
Volume = 100 mL = 0.1 L.

Step 3: Solve for Osmotic Pressure ()
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