A graph of vapour pressure and temperature for three different liquids X, Y and Z is shown below: The following…
Solutions · Class 12 · JEE Main Previous Year Question
A graph of vapour pressure and temperature for three different liquids X, Y and Z is shown below:
The following inferences are made:
(A) X has higher intermolecular interactions compared to Y.
(B) X has lower intermolecular interactions compared to Y.
(C) Z has lower intermolecular interactions compared to Y.
The correct inferences is/are:
- a✓
(A) and (C)
- b
(A)
- c
(B)
- d
(C)
(A) and (C)
Strategy:\n> Vapour pressure is an indicator of intermolecular forces. Liquids with stronger attractions hold their molecules more tightly and thus have a lower vapour pressure at a given temperature.\n\nStep 1: Observe the graph\nLook at the vapour pressures of X, Y, and Z at a constant temperature.\n- The curve for X is the lowest (lowest ).\n- The curve for Z is the highest (highest ).\n- Order of vapour pressure: .\n\nStep 2: Relate Vapour Pressure to Intermolecular Interactions\nStrength of interaction index is inverse to vapour pressure:\n- .\n\nStep 3: Evaluate inferences\n- (A) X has higher interactions than Y: Correct, because .\n- (B) X has lower interactions than Y: Incorrect.\n- (C) Z has lower interactions than Y: Correct, because .\n\nConclusion: (A) and (C) are correct.\n\n
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