A solution of two miscible liquids showing negative deviation from Raoult's law will have:
Solutions · Class 12 · JEE Main Previous Year Question
A solution of two miscible liquids showing negative deviation from Raoult's law will have:
- a
increased vapour pressure, increased boiling point
- b
increased vapour pressure, decreased boiling point
- c
decreased vapour pressure, decreased boiling point
- d✓
decreased vapour pressure, increased boiling point
decreased vapour pressure, increased boiling point
Strategy:\n> Negative deviation means A-B interactions are stronger than pure liquid interactions. This reduces the tendency of molecules to escape into the vapor phase.\n\nAnalysis:\n1. Vapor Pressure: Stronger attractions harder to evaporate decreased vapor pressure.\n2. Boiling Point: A lower vapor pressure means a higher temperature is required to reach atmospheric pressure increased boiling point.\n\n
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