Identify the mixture that shows positive deviations from Raoult's Law

Strategy:\n> Positive deviation occurs when intermolecular forces between two different molecules (A-B) are weaker than in the pure components. This is ty\pically observed when mixing a polar molecule with a non-polar one or when breaking existing hydrogen bonds.\n\nStep 1: Evaluate the options\n1. Acetone + Aniline: Forms hydrogen bonds (stronger A-B). $\rightarrow$ Negative Deviation\n2. Chloroform + Benzene: Forms weak hydrogen bonds/interactions. $\rightarrow$ Negative Deviation\n3. Chloroform + Acetone: Strong hydrogen bonding occurs between the $H$ of $\ce{CHCl3}$ and the $O$ of acetone. $\rightarrow$ Negative Deviation\n4. Acetone + $\ce{CS2}$: $\ce{CS2}$ is non-polar and disrupts the dipole-dipole attractions in acetone without forming any significant new bonds. $\rightarrow$ Positive Deviation\n\nConclusion:\nCarbon disulfide ($\ce{CS2}$) and acetone show positive deviation.\n\n$\boxed{\\text{Answer: (4)}}$