A set of solutions is prepared using 180 g of water as a solvent and 10 g of different non-volatile solutes A, B and C.…
Solutions · Class 12 · JEE Main Previous Year Question
A set of solutions is prepared using 180 g of water as a solvent and 10 g of different non-volatile solutes A, B and C. The relative lowering of vapour pressure in the presence of these solutes are in the order
[Given, molar mass of A = 100 g mol⁻¹; B = 200 g mol⁻¹; C = 10,000 g mol⁻¹]
- a
B > C > A
- b
C > B > A
- c✓
A > B > C
- d
A > C > B
A > B > C
Strategy:\n> Relative lowering of vapour pressure (RLVP) is a colligative property defined by . Since the mass of solute and solvent are the same, RLVP is inversely proportional to the molar mass of the solute.\n\nStep 1: Compare moles of each solute\nCommon mass = 10 g.\n- \n- \n- \n\nStep 2: Relate moles to RLVP\nFor a fixed amount of solvent (180 g water = 10 mol), higher moles of solute result in a higher mole fraction, and thus higher RLVP.\nOrder: .\n\n
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