JEE Main · 2020 · Shift-ImediumSOL-114

At 35°C, the vapour pressure of CS2, is 512 mm Hg and that of acetone is 144 mmHg. A solution of CS2 in acetone has a…

Solutions · Class 12 · JEE Main Previous Year Question

Question

At 35°C, the vapour pressure of CS2\mathrm{CS_2}, is 512 mm Hg and that of acetone is 144 mmHg. A solution of CS2\mathrm{CS_2} in acetone has a total vapour pressure of 600 mmHg. The false statement amongst the following is:

Options
  1. a

    Raoult's law is not obeyed by this system

  2. b

    a mixture of 100 mL CS2\mathrm{CS_2} and 100 mL acetone has a volume < 200 mL

  3. c

    CS2\mathrm{CS_2} and acetone are less attracted to each other than to themselves

  4. d

    heat must be absorbed in order to produce the solution at 35°C

Correct Answerb

a mixture of 100 mL CS2\mathrm{CS_2} and 100 mL acetone has a volume < 200 mL

Detailed Solution

Strategy:\n> Compare the actual measured total pressure (600 mm Hg) with the individual pure vapour pressures (144 and 512 mm Hg). If the total pressure exceeds the highest individual pressure, the system shows extreme positive deviation from Raoult's Law.\n\nStep 1: Identify the deviation type\nThe total pressure (600) is greater than both P\ceCS2P_{\ce{CS2}}^\circ (512) and PtextacetoneP_{\\text{acetone}}^\circ (144).\nThis indicates positive deviation.\n\nStep 2: Evaluate statement (2)\n"The volume of a mixture... has a volume < 200 mL".\nIn systems with positive deviation, A–B attractions are weaker than pure state attractions. Molecules push away from each other, leading to a volume increase (ΔVtextmix>0\Delta V_{\\text{mix}} > 0).\nThus, the volume will be greater than 200 mL. Statement (2) is false.\n\ntextAnswer:(2)\boxed{\\text{Answer: (2)}}

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At 35°C, the vapour pressure of CS2, is 512 mm Hg and that of acetone is 144 mmHg. A solution of… (JEE Main 2020) | Canvas Classes