The orbital having two radial as well as two angular nodes is:

🧠 The Node Summation We are looking for an orbital where:

1. Angular Nodes ($l$) = 2. This means it must be a d-orbital.
2. Radial Nodes ($n - l - 1$) = 2.

🗺️ The Solving Sequence

1. Identify $l$: $l = 2$ (d-orbital).
2. Solving for $n$: $n - 2 - 1 = 2$ $n - 3 = 2 \implies n = 5$
3. Conclusion: The orbital is 5d.

⚡ The "Total Nodes" Anchor Total nodes $= ext{Radial} + ext{Angular} = 2 + 2 = 4$. Since Total Nodes $= n-1$, we have $n-1 = 4$, which means $n=5$. With $l=2$, it's 5d.

⚠️ Common Traps Be careful with $4d$. It has 2 angular nodes but only $4-2-1=1$ radial node. You need one shell higher!

$\boxed{\text{Answer: (a)}}$