JEE Main · 2022 · Shift-IImediumATOM-109

Which of the following is the correct plot for the probability density 2(r) as a function of distance 'r' of the…

Structure of Atom · Class 11 · JEE Main Previous Year Question

Question

Which of the following is the correct plot for the probability density ψ2(r)\psi^2(r) as a function of distance 'rr' of the electron from the nucleus for 2s orbital?

Options
  1. a

    image

  2. b

    image

  3. c

    image

  4. d

    image

Correct Answerb

image

Detailed Solution

🧠 The Probability Peak Probability density (ψ2\psi^2) is the likelihood of finding an electron at a specific distance from the nucleus. For "s" orbitals, the electron is most likely to be found... right at the start (r=0r=0).

🗺️ The 2s Profile

  1. At the Nucleus: Unlike p or d orbitals, s-orbitals have maximum density at r=0r=0. The graph starts at its peak.
  2. The Node: A 2s orbital has 201=12 - 0 - 1 = 1 radial node. The graph must touch the x-axis exactly once.
  3. The Second Max: After the node, the wave function has a smaller "hump" before decaying to zero at infinity.
  4. Conclusion: The graph must start high, cross zero once, and then have a second smaller peak. This is correctly shown in Option (b).

The "Touch and Go" Rule Wavelength density ψ2\psi^2 can never be negative. So the graph should never dip below the x-axis; it merely "kisses" it at the node.

⚠️ Common Traps Don't pick a graph that starts at zero! Only p, d, and f orbitals start at zero. All s-orbitals are "nuclear touchers."

Answer: (b)\boxed{\text{Answer: (b)}}

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