Which of the following is the correct plot for the probability density 2(r) as a function of distance 'r' of the…
Structure of Atom · Class 11 · JEE Main Previous Year Question
Which of the following is the correct plot for the probability density as a function of distance '' of the electron from the nucleus for 2s orbital?
- a
- b✓
- c
- d
🧠 The Probability Peak Probability density () is the likelihood of finding an electron at a specific distance from the nucleus. For "s" orbitals, the electron is most likely to be found... right at the start ().
🗺️ The 2s Profile
- At the Nucleus: Unlike p or d orbitals, s-orbitals have maximum density at . The graph starts at its peak.
- The Node: A 2s orbital has radial node. The graph must touch the x-axis exactly once.
- The Second Max: After the node, the wave function has a smaller "hump" before decaying to zero at infinity.
- Conclusion: The graph must start high, cross zero once, and then have a second smaller peak. This is correctly shown in Option (b).
⚡ The "Touch and Go" Rule Wavelength density can never be negative. So the graph should never dip below the x-axis; it merely "kisses" it at the node.
⚠️ Common Traps Don't pick a graph that starts at zero! Only p, d, and f orbitals start at zero. All s-orbitals are "nuclear touchers."
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The wave function () of 2s is given by: _{2s} = {1}{2{2}}({1}{a_0})^{1/2}(2 - {r}{a_0})e^{-r/2a_0} At r = r0, radial node is formed. Thus r0 in terms of a0 is:
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The plots of radial distribution functions for various orbitals of hydrogen atom against 'r' are given below. The correct plot for 3s orbital is:
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