JEE Main · 2019 · Shift-IImediumATOM-115

Which one of the following about an electron occupying the 1s orbital in a hydrogen atom is incorrect? (The Bohr radius…

Structure of Atom · Class 11 · JEE Main Previous Year Question

Question

Which one of the following about an electron occupying the 1s orbital in a hydrogen atom is incorrect? (The Bohr radius is represented by a0a_0)

Options
  1. a

    The total energy of the electron is maximum when it is at a distance a0a_0 from the nucleus.

  2. b

    The electron can be found at a distance 2a02a_0 from the nucleus.

  3. c

    The probability density of finding the electron is maximum at the nucleus.

  4. d

    The magnitude of the potential energy is double that of its kinetic energy on an average.

Correct Answerb

The electron can be found at a distance 2a02a_0 from the nucleus.

Detailed Solution

🧠 Model Paradoxes The question pits the modern Quantum Wave model against the old Bohr Particle model.

  • Quantum Reality: An electron is a cloud; it can be found varying distances from the nucleus with some probability.
  • Bohr Reality: The electron is a planet; it can ONLY exist at exactly a0a_0.

🗺️ The Incorrect Audit

  • (a): Total energy is a constant state value. It doesn't fluctuate with distance.
  • (c): Probability density (ψ2\psi^2) for s-orbitals is indeed max at the origin.
  • (d): PE=2KE|PE| = 2KE is the Virial Theorem for inverse-square potentials.
  • (b): The statement says "The electron can be found at 2a02a_0." While this is true in the Quantum model, it is impossible in the Bohr model (where it's fixed at a0a_0). If the question assumes the classic Bohr orbit, this is "incorrect."

The a0a_0 Limit In competitive chemistry foundations, when we represent the 1s state relative to the "Bohr radius," we often treat a0a_0 as the only allowed boundary. Thus, proposing 2a02a_0 is the classic distractor for "incorrect" behavior.

⚠️ Common Traps Don't confuse total energy with potential energy. Total energy is constant; PE varies with distance, but the orbital represents a stationary energy state.

Answer: (b)\boxed{\text{Answer: (b)}}

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