JEE Main · 2020 · Shift-IIeasyTHERMO-046

Five moles of ideal gas at 1 bar and 298 K is expanded into vacuum to double the volume. The work done is:

Thermodynamics · Class 11 · JEE Main Previous Year Question

Question

Five moles of ideal gas at 1 bar and 298 K is expanded into vacuum to double the volume. The work done is:

Options
  1. a

    Cv(T2T1)C_v(T_2-T_1)

  2. b

    RT(V2V1)-RT(V_2-V_1)

  3. c

    RTlnV2/V1-RT\ln V_2/V_1

  4. d

    Zero

Correct Answerd

Zero

Detailed Solution

🧠 Free expansion into vacuum: no opposing force, so no work is done Pext=0P_{\text{ext}} = 0 (vacuum). Work = PextΔV=0-P_{\text{ext}} \cdot \Delta V = 0.

None of the other formulas apply:

  • (a) Cv(T2T1)C_v(T_2 - T_1) = ΔU\Delta U, not work — and ΔT=0\Delta T = 0 for isothermal ideal gas anyway.
  • (b) and (c) are not standard work expressions for free expansion.

For free expansion of an ideal gas: w=0w = 0, q=0q = 0, ΔU=0\Delta U = 0, ΔT=0\Delta T = 0.

Answer: (d)\boxed{\text{Answer: (d)}}

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