JEE Main Β· 2025 Β· Shift-IIhardTHERMO-142

Which of the following graphs correctly represents the variation of thermodynamic properties of Haber's process? (N2(g)…

Thermodynamics Β· Class 11 Β· JEE Main Previous Year Question

Question

Which of the following graphs correctly represents the variation of thermodynamic properties of Haber's process? (\ceN2(g)+3H2(g)<=>2NH3(g)\ce{N2(g) + 3H2(g) <=> 2NH3(g)})

Options
  1. a

    Graph (a): βˆ’Ξ”HR∘/T-\Delta H_R^\circ/T decreases; βˆ’Ξ”GR∘/T-\Delta G_R^\circ/T decreases; βˆ’Ξ”SR∘-\Delta S_R^\circ constant positive

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  2. b

    Graph (b): βˆ’Ξ”HR∘-\Delta H_R^\circ constant; βˆ’Ξ”GR∘/T-\Delta G_R^\circ/T and βˆ’Ξ”SR∘/T-\Delta S_R^\circ/T vary

  3. c

    Graph (c): βˆ’Ξ”SR∘-\Delta S_R^\circ positive large; βˆ’Ξ”HR∘-\Delta H_R^\circ negative

  4. d

    Graph (d): βˆ’Ξ”GR∘/T-\Delta G_R^\circ/T increases with T

Correct Answera

Graph (a): βˆ’Ξ”HR∘/T-\Delta H_R^\circ/T decreases; βˆ’Ξ”GR∘/T-\Delta G_R^\circ/T decreases; βˆ’Ξ”SR∘-\Delta S_R^\circ constant positive

Detailed Solution

🧠 Haber's process: Ξ”H<0\Delta H < 0 and Ξ”S<0\Delta S < 0 β€” both properties decrease with temperature in a Ellingham-style plot For \ceN2+3H2βˆ’>2NH3\ce{N2 + 3H2 -> 2NH3}: the reaction is exothermic (Ξ”HR<0\Delta H_R < 0) and entropy decreases (Ξ”SR<0\Delta S_R < 0) because gas moles decrease from 4 to 2.

Analyzing the thermodynamic plots:

  • βˆ’Ξ”HR∘/T-\Delta H_R^\circ / T increases as TT increases (since Ξ”HR\Delta H_R is roughly constant, dividing by larger TT reduces the magnitude of the negative value, making βˆ’Ξ”H/T-\Delta H / T less positive).
  • βˆ’Ξ”SR∘-\Delta S_R^\circ is constant and positive (since Ξ”SR<0\Delta S_R < 0, its negation is >0> 0).
  • βˆ’Ξ”GR∘/T=βˆ’Ξ”HR∘/T+Ξ”SR∘-\Delta G_R^\circ / T = -\Delta H_R^\circ / T + \Delta S_R^\circ decreases with temperature (the positive entropy term gets subtracted increasingly by the diminishing βˆ’Ξ”H/T-\Delta H/T contribution).

Graph (a) correctly shows βˆ’Ξ”H/T-\Delta H/T decreasing, βˆ’Ξ”S-\Delta S constant and positive, and βˆ’Ξ”G/T-\Delta G/T decreasing.

Answer:Β (a)\boxed{\text{Answer: (a)}}

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