JEE Main · 2019 · Shift-IIeasyTHERMO-061

The process with negative entropy change is:

Thermodynamics · Class 11 · JEE Main Previous Year Question

Question

The process with negative entropy change is:

Options
  1. a

    Synthesis of ammonia from N2\text{N}_2 and H2\text{H}_2

  2. b

    Dissolution of iodine in water

  3. c

    Dissociation of CaSO4(s)\text{CaSO}_4(s) to CaO(s)\text{CaO}(s) and SO3(g)\text{SO}_3(g)

  4. d

    Sublimation of dry ice

Correct Answera

Synthesis of ammonia from N2\text{N}_2 and H2\text{H}_2

Detailed Solution

🧠 Entropy decreases when gas moles decrease or when molecules become more ordered Check each process for the direction of disorder change.

🗺️ Checking each option (a) \ceN2(g)+3H2(g)>2NH3(g)\ce{N2(g) + 3H2(g) -> 2NH3(g)}: 4 mol gas → 2 mol gas, Δng=2\Delta n_g = -2, fewer gas molecules → ΔS<0\Delta S < 0

(b) Dissolution of iodine in water: solid dissolves into solution, more dispersed → ΔS>0\Delta S > 0

(c) \ceCaSO4(s)>CaO(s)+SO3(g)\ce{CaSO4(s) -> CaO(s) + SO3(g)}: gas is produced → ΔS>0\Delta S > 0

(d) Sublimation of dry ice (\ceCO2\ce{CO2}): solid → gas → ΔS>0\Delta S > 0

Only option (a) gives ΔS<0\Delta S < 0.

⚠️ Trap: Don't mistake "the reaction requires energy" for "entropy decreases". Ammonia synthesis is exothermic (favours products enthalpy-wise) and also has ΔS<0\Delta S < 0 — both factors must be weighed for spontaneity.

Answer: (a)\boxed{\text{Answer: (a)}}

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