JEE Main · 2020 · Shift-IeasyTHERMO-122

If enthalpy of atomization for Br2(l) is x\,kJ/mol and bond enthalpy for Br2 is y\,kJ/mol, the relation between them:

Thermodynamics · Class 11 · JEE Main Previous Year Question

Question

If enthalpy of atomization for Br2(l)\text{Br}_2(l) is xkJ/molx\,\text{kJ/mol} and bond enthalpy for Br2\text{Br}_2 is ykJ/moly\,\text{kJ/mol}, the relation between them:

Options
  1. a

    x=yx=y

  2. b

    does not exist

  3. c

    x>yx>y

  4. d

    x<yx<y

Correct Answerc

x>yx>y

Detailed Solution

🧠 Atomization from liquid adds vaporization on top of bond dissociation Bond enthalpy is defined for gas-phase molecules. Atomization of \ceBr2(l)\ce{Br2(l)} requires first vaporizing the liquid, then breaking the bond — two steps, both endothermic.

x=ΔHvap+yx = \Delta H_{\text{vap}} + y

Since ΔHvap>0\Delta H_{\text{vap}} > 0, it follows that x>yx > y.

Answer: (c) x>y\boxed{\text{Answer: (c) } x > y}

Practice this question with progress tracking

Want timed practice with adaptive difficulty? Solve this question (and hundreds more from Thermodynamics) inside The Crucible, our adaptive practice platform.

If enthalpy of atomization for Br2(l) is x\,kJ/mol and bond enthalpy for Br2 is y\,kJ/mol, the… (JEE Main 2020) | Canvas Classes