JEE Main · 2025 · Shift-IImediumTHERMO-149

The correct statement amongst the following is: (A) The term 'standard state' implies that the temperature is 0°C (B)…

Thermodynamics · Class 11 · JEE Main Previous Year Question

Question

The correct statement amongst the following is:

(A) The term 'standard state' implies that the temperature is 0°C

(B) The standard state of pure gas is the pure gas at a pressure of 1 bar and temperature 273 K

(C) ΔfH298\Delta_f H^\circ_{298} is zero for O(g)

(D) ΔfH500\Delta_f H^\circ_{500} is zero for \ceO2(g)\ce{O2(g)}

Options
  1. a

    A only

  2. b

    B only

  3. c

    C only

  4. d

    D only

Correct Answerd

D only

Detailed Solution

🧠 Standard enthalpy of formation is zero for elements in their standard reference state — at ANY temperature "Standard state" specifies 1 bar pressure but not a fixed temperature. The reference temperature is arbitrary (often 298 K, but ΔfH\Delta_f H^\circ can be defined at any TT). For any element in its most stable form at that pressure and temperature, ΔfH=0\Delta_f H^\circ = 0 by definition.

Evaluating statements:

  • (A) False — standard state does not require 0°C.
  • (B) False — standard state specifies 1 bar but does not require 273 K.
  • (C) False — \ceO(g)\ce{O(g)} is an atom, not the standard form of oxygen. The standard state is \ceO2(g)\ce{O2(g)}, so ΔfH(\ceO(g))0\Delta_f H^\circ(\ce{O(g)}) \neq 0.
  • (D) True — \ceO2(g)\ce{O2(g)} is the standard reference form of oxygen at any temperature.

Answer: (d)\boxed{\text{Answer: (d)}}

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