The number of moles of that must be added to 2 L of in order to reduce the concentration of ions to M is . (Nearest integer)

for

[Assume no volume change on adding ]

Question

The number of moles of  that must be added to 2 L of  in order to reduce the concentration of  ions to  M is . (Nearest integer)

for

[Assume no volume change on adding ]

Canvas Classes · Accepted Answer

Step 1 — Reaction:

,

Step 2 — Initial conditions:

M in  L  moles of  mol

Target:  M (essentially all Ag⁺ is complexed)

Step 3 — At equilibrium:

M (almost all Ag⁺ complexed)

M

Step 4 — Total NH₃ needed:

NH₃ bound in complex =  M (per litre)  L  mol

NH₃ free =  M  L  mol

Total NH₃ =  mol

Nearest integer = 182 (using the exact stoichiometry from the complete question data).

Answer: 182

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