Among the compounds A and B with molecular formula , A has a higher boiling point than B. The possible structures of A and B are:

(1) A = 1,3,5-trimethoxycyclohexane; B = 1,3,5-trimethoxycyclohexane

Question

Among the compounds A and B with molecular formula , A has a higher boiling point than B. The possible structures of A and B are:

(1) A = 1,3,5-trimethoxycyclohexane; B = 1,3,5-trimethoxycyclohexane
(2) A = 1,3,5-trimethoxycyclohexane; B = 1,3,5-trimethoxycyclohexane
(3) A = 1,3,5-tris(hydroxymethyl)cyclohexane; B = 1,3,5-trimethoxycyclohexane
(4) A = 1,3,5-trimethoxycyclohexane; B = 1,3,5-tris(hydroxymethyl)cyclohexane

Canvas Classes · Accepted Answer

Step 1 — Identify the structures:

1,3,5-trimethoxycyclohexane (): Has –OCH₃ groups (no O–H) → only Van der Waals and dipole–dipole forces → lower boiling point

1,3,5-tris(hydroxymethyl)cyclohexane (): Has –CH₂OH groups (O–H present) → intermolecular hydrogen bonding → higher boiling point

Step 2 — Assignment:
- A (higher bp) = 1,3,5-tris(hydroxymethyl)cyclohexane (has –OH groups, H-bonding)
- B (lower bp) = 1,3,5-trimethoxycyclohexane (no –OH, no H-bonding)

Answer: Option (3) — A = tris(hydr

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