The type of hybridization and number of lone pair(s) of electrons of Xe in , respectively, are:

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Step 1 — Electron pairs on Xe in :
- Xe bonds: 1 O (double bond counts as 1 pair) + 4 F = 5 bonds
- Lone pairs on Xe: 1
- Total electron pairs = 5 + 1 = 6

Step 2 — Hybridization:
- 6 electron pairs → sp³d² hybridization

Step 3 — Shape:
- 5 bonds + 1 lone pair → square pyramidal

Answer: Option (1) — sp³d² and 1 lone pair

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