The compound that has the largest H–M–H bond angle (M = N, O, S, C) is:

Question

Canvas Classes · Accepted Answer

Step 1 — Bond angles in each compound:

| Compound | M | Hybridization | Lone pairs | Bond angle |
|----------|---|---------------|-----------|------------|
|  | O | sp³ | 2 | 104.5° |
|  | N | sp³ | 1 | 107° |
|  | S | sp³ (mostly p) | 2 | ~92° |
|  | C | sp³ | 0 | 109.5° |

Step 2 — Reasoning:
- : No lone pairs → pure tetrahedral angle of 109.5° (maximum)
- : 1 lone pair compresses angle to 107°
- : 2 lone pairs compress angle to 104.5°
- : S uses mostly p orbitals → ~92°

Answer: Option (4) —

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