1.46 g of a biopolymer dissolved in a 100 mL water at 300 K exerted an osmotic pressure of bar. The molar mass of the biopolymer is g mol⁻¹. (Round off to the Nearest Integer)

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Question

1.46 g of a biopolymer dissolved in a 100 mL water at 300 K exerted an osmotic pressure of  bar. The molar mass of the biopolymer is  g mol⁻¹. (Round off to the Nearest Integer)

[Use: ]

Canvas Classes · Accepted Answer

Strategy:
 Use the osmotic pressure formula rearranged for molar mass: . Pay close attention to unit exponents in the final answer.

Step 1: Align given parameters
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Step 2: Calculate Molar Mass ()

Step 3: Convert to  form
.
Rounding to the nearest integer: 15.

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