When 3.00 g of a substance 'X' is dissolved in 100 g of , it raises the boiling point by 0.60 K. The molar mass of the substance 'X' is g mol⁻¹. (Nearest integer).

[Given: for is 5.0 K kg mol⁻¹]

Question

When 3.00 g of a substance 'X' is dissolved in 100 g of , it raises the boiling point by 0.60 K. The molar mass of the substance 'X' is  g mol⁻¹. (Nearest integer).

[Given:  for  is 5.0 K kg mol⁻¹]

Canvas Classes · Accepted Answer

Strategy:
 Use the boiling point elevation formula  to find the molality, then use the mass of the solvent to calculate the molar mass of the solute.

Step 1: Calculate molality ()
, .

Step 2: Determine moles of solute
Mass of  (solvent) = 100 g = 0.1 kg.

Step 3: Calculate molar mass ()
Mass of substance 'X' = 3.00 g.

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