2.5 g of protein containing only glycine is dissolved in water to make 500 mL of solution. The osmotic pressure of this solution at 300 K is found to be bar. The total number of glycine units presen

Question

2.5 g of protein containing only glycine  is dissolved in water to make 500 mL of solution. The osmotic pressure of this solution at 300 K is found to be  bar. The total number of glycine units present in the protein is

(Given: )

Canvas Classes · Accepted Answer

Step 1: Find moles of protein using osmotic pressure

Step 2: Find molar mass of protein

Step 3: Find number of glycine units

Molar mass of glycine () = 2(12) + 5(1) + 14 + 2(16) = 24 + 5 + 14 + 32 = 75 g/mol

In a polypeptide, each glycine unit loses water (18 g/mol) when forming a peptide bond. So each glycine residue contributes approximately 57 g/mol (75 − 18 = 57).

Number of glycine units:

(Using 75 g/mol per glycine unit as the approximate calculation gives 330)

Final Answ

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