0.400 g of an organic compound (X) gave 0.376 g of AgBr in Carius method for estimation of bromine. % of bromine in the compound (X) is .

(Given: Molar mass AgBr = 188 , Br = 80 )

Question

0.400 g of an organic compound (X) gave 0.376 g of AgBr in Carius method for estimation of bromine. % of bromine in the compound (X) is .

(Given: Molar mass AgBr = 188 , Br = 80 )

Canvas Classes · Accepted Answer

Step 1: Recall the Carius Method Formula for Bromine

In the Carius method:

Step 2: Substitute the Given Values

-  = 0.376 g
-  = 0.400 g
- Molar mass of AgBr = 188 g/mol
- Molar mass of Br = 80 g/mol

Step 3: Calculate the Percentage

Answer: 40%

Key Points to Remember:
- Bromine formula: 
- The fraction  is the mass fraction of Br in AgBr
- Verify: 0.376 × 80/188 = 0.160 g Br; 0.160/0.400 × 100 = 40% ✓
- For Cl: use 35.5/143.5; for I: use 127/235

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