In sulphur estimation, 0.471 g of an organic compound gave 1.4439 g of barium sulphate. The percentage of sulphur in the compound is (Nearest Integer)

(Given: Atomic mass Ba: 137 u, S: 32 u, O: 16 u

Question

In sulphur estimation, 0.471 g of an organic compound gave 1.4439 g of barium sulphate. The percentage of sulphur in the compound is  (Nearest Integer)

(Given: Atomic mass Ba: 137 u, S: 32 u, O: 16 u)

Canvas Classes · Accepted Answer

Step 1: Recall the Sulphur Estimation Formula

In the Carius method for sulphur:

Where molar mass of  = 137 + 32 + 4(16) = 137 + 32 + 64 = 233 g/mol

Step 2: Calculate Mass of Sulphur in BaSO₄

Given:  = 1.4439 g

Step 3: Calculate the Percentage

= 0.471 g

Answer: 42 (nearest integer)

Key Points to Remember:
- BaSO₄ molar mass = 233 g/mol (137 + 32 + 64)
- Sulphur formula: 
- The fraction 
- Carius method for S: sealed Carius tube + fuming HNO₃ → BaSO₄ precipitate (gravimetric)

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