Ch. 2 | Solutions0/13

Ideal and Non-Ideal Solutions

Deviations from Raoult's law, azeotropes, and why like dissolves like

Analogical ReasoningLevel 3 · Analysis

When ethanol and water are mixed, the total volume is slightly less than the sum of the pure volumes — the mixture "contracts." When acetone and carbon disulphide are mixed, the volume expands slightly. What do these observations reveal about the intermolecular forces in each mixture — and what would you predict about how their boiling points compare to Raoult's law predictions?

Real Life Hook

Pure ethanol boils at 78.4°C. Pure water boils at 100°C. You might expect that a mixture would boil somewhere between these two temperatures. But at 95.6% ethanol, the mixture boils at 78.1°C — lower than pure ethanol. This is a minimum-boiling azeotrope: a mixture that boils at a lower temperature than either pure component. You can't distil it any further — the vapour has the same composition as the liquid. This is why you cannot make 100% pure alcohol by distillation alone. Every bottle of whisky, rum, and vodka is a living demonstration of non-ideal solution behaviour.

Ideal Solutions

An ideal solution obeys Raoult's law at every concentration. It forms when:

  • A-B intermolecular forces = A-A and B-B forces
  • ΔHmix=0\Delta H_{\text{mix}} = 0 (no heat released or absorbed on mixing)
  • ΔVmix=0\Delta V_{\text{mix}} = 0 (no volume change on mixing)

Examples: benzene + toluene, ethanol + methanol, nn-hexane + nn-heptane (similar molecules, similar forces)

Non-Ideal Solutions — Deviations from Raoult's Law

Positive vs Negative Deviation

Positive Deviation

  • p_observed > p_Raoult (higher vapour pressure than predicted)
  • A-B interactions weaker than A-A and B-B
  • ΔH_mix > 0 (endothermic mixing)
  • ΔV_mix > 0 (volume expansion)
  • Forms minimum-boiling azeotrope
  • Examples: ethanol-water, acetone-CS₂, acetone-benzene
VS

Negative Deviation

  • p_observed < p_Raoult (lower vapour pressure than predicted)
  • A-B interactions stronger than A-A and B-B
  • ΔH_mix < 0 (exothermic mixing)
  • ΔV_mix < 0 (volume contraction)
  • Forms maximum-boiling azeotrope
  • Examples: acetone-chloroform, HNO₃-water, phenol-aniline

Azeotropes

An azeotrope is a mixture that boils at a constant temperature and has the same composition in vapour and liquid phases — it cannot be further separated by simple distillation.

Minimum-boiling azeotrope (positive deviation):

  • Boils below both pure components
  • Example: ethanol-water at 95.6% ethanol, 78.1°C
  • Absolute alcohol cannot be made by distillation alone

Maximum-boiling azeotrope (negative deviation):

  • Boils above both pure components
  • Example: HNOX3\ce{HNO3}-water at 68% HNOX3\ce{HNO3}, 120.5°C
  • Purifying by distillation produces the azeotropic composition, not pure component
🖼 Image PendingVapour pressure vs composition curves showing positive and negative deviation from Raoult's law

AI Generation Prompt

Two side-by-side vapour pressure vs mole fraction graphs. Left graph labelled 'Positive Deviation': X-axis mole fraction of A (0 to 1), Y-axis vapour pressure. Show dashed straight Raoult's law line between p°_B and p°_A. Show solid curve bulging ABOVE the dashed line, labelled 'Observed p_total'. Label region 'p > Raoult prediction'. Right graph labelled 'Negative Deviation': same axes. Show dashed straight Raoult's law line. Show solid curve dipping BELOW the dashed line, labelled 'Observed p_total'. Label region 'p < Raoult prediction'. Both graphs show component contributions p_A and p_B. Dark background, orange accent labels, clean technical illustration style.

📸 Non-ideal solutions: curves bulge above (positive deviation) or below (negative deviation) the straight Raoult's law line
JEE / NEET Exam InsightJEE / NEET
Memory aid for deviations:
    Positive deviation → weaker new interactions → molecules escape more easily → higher vapour pressure → lower boiling point
    Negative deviation → stronger new interactions → molecules escape less easily → lower vapour pressure → higher boiling point
Azeotrope exam pattern: "Which cannot be separated by distillation?" → Azeotrope.
JEE frequently tests: Acetone + chloroform → negative deviation (C=O of acetone forms H-bond with CHCl₃). Ethanol + water → positive deviation (H-bonding between unlike molecules is weaker than water-water H-bonds).
Quick Check

Q1.Which conditions must both be satisfied for a solution to be ideal?