Raoult's Law and Vapour Pressure of Solutions
How dissolved substances reduce vapour pressure — and Dalton's law of composition
You mix equal moles of benzene (vapour pressure = 95 mmHg) and toluene (vapour pressure = 29 mmHg) at 25°C. A classmate says: "The total vapour pressure must be close to 95 mmHg since benzene dominates with its high vapour pressure." Another says it must be exactly 62 mmHg — the arithmetic mean. Who is right, and how would you calculate the true answer?
François-Marie Raoult spent twelve years (1878–1890) patiently measuring the vapour pressures of hundreds of solutions. He discovered the same law applied to all dilute solutions regardless of the chemical identity of the solute — as long as it was non-volatile. His insight was that only the solvent evaporates, and its ability to evaporate is reduced in proportion to how much solute is blocking the surface. A simple geometric idea that now underpins everything from industrial distillation to osmotic drug delivery.
Raoult's Law — For Volatile Solutes
For a solution of two volatile components (A and B), each component obeys Raoult's law independently:
By Dalton's law of partial pressures, the total vapour pressure:
where and are the vapour pressures of pure A and pure B, and , are their mole fractions in solution.
Key result: lies between and — the total pressure is always intermediate.
Raoult's Law — For Non-Volatile Solutes
When the solute is non-volatile (solid dissolved in liquid — e.g. NaCl in water), it contributes zero vapour pressure. Only the solvent evaporates:
Since (mole fraction of solvent = 1 − mole fraction of solute):
Relative lowering of vapour pressure (RLVP):
RLVP equals the mole fraction of the solute — a colligative property that depends only on how many solute particles are present, not what they are.
AI Generation Prompt
Vapour pressure vs mole fraction graph for benzene-toluene ideal solution. X-axis: mole fraction of benzene (0 to 1). Y-axis: vapour pressure in mmHg (0 to 120). Three lines: (1) p_toluene: linear from 29 mmHg at x=0 to 0 at x=1, in blue. (2) p_benzene: linear from 0 at x=0 to 95 mmHg at x=1, in orange. (3) p_total: linear from 29 mmHg at x=0 to 95 mmHg at x=1, in white/amber, labelled p_total = p°_toluene × x_toluene + p°_benzene × x_benzene. Mark the midpoint at x_benzene = 0.5 showing p_total = 62 mmHg. Dark background, orange accent labels, clean technical illustration style.
Remember
Raoult's law applies to the solvent, not the solute. The solvent's partial pressure = .
RLVP = mole fraction of solute: — valid for dilute solutions only.
Composition of vapour ≠ composition of liquid. The vapour is richer in the more volatile component. This is the basis of distillation.
Problem
The vapour pressure of pure benzene at 25°C is 0.850 bar. A non-volatile, non-electrolyte solid weighing 0.5 g is dissolved in 39.0 g of benzene (molar mass = 78 g/mol). The vapour pressure of the solution is 0.845 bar. Find the molar mass of the solid.
Q1.According to Raoult's law, the partial vapour pressure of a component in a liquid mixture is:
You mix equal moles of benzene (vapour pressure = 95 mmHg) and toluene (vapour pressure = 29 mmHg) at 25°C. A classmate says: "The total vapour pressure must be close to 95 mmHg since benzene dominates with its high vapour pressure." Another says it must be exactly 62 mmHg — the arithmetic mean. Who is right, and how would you calculate the true answer?
François-Marie Raoult spent twelve years (1878–1890) patiently measuring the vapour pressures of hundreds of solutions. He discovered the same law applied to all dilute solutions regardless of the chemical identity of the solute — as long as it was non-volatile. His insight was that only the solvent evaporates, and its ability to evaporate is reduced in proportion to how much solute is blocking the surface. A simple geometric idea that now underpins everything from industrial distillation to osmotic drug delivery.
Raoult's Law — For Volatile Solutes
For a solution of two volatile components (A and B), each component obeys Raoult's law independently:
By Dalton's law of partial pressures, the total vapour pressure:
where and are the vapour pressures of pure A and pure B, and , are their mole fractions in solution.
Key result: lies between and — the total pressure is always intermediate.
Raoult's Law — For Non-Volatile Solutes
When the solute is non-volatile (solid dissolved in liquid — e.g. NaCl in water), it contributes zero vapour pressure. Only the solvent evaporates:
Since (mole fraction of solvent = 1 − mole fraction of solute):
Relative lowering of vapour pressure (RLVP):
RLVP equals the mole fraction of the solute — a colligative property that depends only on how many solute particles are present, not what they are.
AI Generation Prompt
Vapour pressure vs mole fraction graph for benzene-toluene ideal solution. X-axis: mole fraction of benzene (0 to 1). Y-axis: vapour pressure in mmHg (0 to 120). Three lines: (1) p_toluene: linear from 29 mmHg at x=0 to 0 at x=1, in blue. (2) p_benzene: linear from 0 at x=0 to 95 mmHg at x=1, in orange. (3) p_total: linear from 29 mmHg at x=0 to 95 mmHg at x=1, in white/amber, labelled p_total = p°_toluene × x_toluene + p°_benzene × x_benzene. Mark the midpoint at x_benzene = 0.5 showing p_total = 62 mmHg. Dark background, orange accent labels, clean technical illustration style.
Problem
The vapour pressure of pure benzene at 25°C is 0.850 bar. A non-volatile, non-electrolyte solid weighing 0.5 g is dissolved in 39.0 g of benzene (molar mass = 78 g/mol). The vapour pressure of the solution is 0.845 bar. Find the molar mass of the solid.
Q1.According to Raoult's law, the partial vapour pressure of a component in a liquid mixture is: