Find out the major product for the following reaction:
Alcohols, Phenols & Ethers · Class 12 · JEE Main Previous Year Question
Find out the major product for the following reaction:
- a
- b✓
- c
- d
Step 1: Acid-catalysed dehydration of 1-methylcyclopentan-1-ol
1-Methylcyclopentan-1-ol is a tertiary alcohol (OH and CH3 both on C1 of the ring).
Protonation of -OH → oxonium ion → loss of water → tertiary cyclopentyl carbocation at C1.
Step 2: Ring expansion (1,2-alkyl shift)
The tertiary cyclopentyl carbocation can undergo a ring expansion via 1,2-carbon shift:
- One of the C-C bonds of the ring migrates to the adjacent carbocation center.
- This converts the 5-membered ring carbocation into a 6-membered ring carbocation (cyclohexyl carbocation).
- The cyclohexyl carbocation (secondary or tertiary) is formed — ring expansion is thermodynamically favorable (6-membered ring > 5-membered ring stability).
Step 3: Elimination
The cyclohexyl carbocation loses a proton to give cyclohexene (or methylcyclopentene depending on which proton is lost).
The major product via ring expansion is a cyclohexene derivative.
Key conceptual principle:
Students often miss ring expansion in carbocation intermediates. When a cyclopentane ring carries a carbocation, 1,2-shift of a ring C-C bond to an adjacent cationic C converts 5-membered → 6-membered ring (more stable).
Key Points to Remember:
- Tertiary carbocations from cyclopentane systems can undergo ring expansion via 1,2-C shift to give cyclohexyl cations.
- 6-membered ring is more stable than 5-membered → ring expansion is thermodynamically favored.
- Ring expansion is a key rearrangement to watch for in acid-catalyzed reactions of cyclic alcohols.
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