JEE Main · 2023 · Shift-IIhardALCO-044

Find out the major product for the following reaction:

Alcohols, Phenols & Ethers · Class 12 · JEE Main Previous Year Question

Question

Find out the major product for the following reaction: image

Options
  1. a

    image

  2. b

    image

  3. c

    image

  4. d

    image

Correct Answerb

image

Detailed Solution

Step 1: Acid-catalysed dehydration of 1-methylcyclopentan-1-ol

1-Methylcyclopentan-1-ol is a tertiary alcohol (OH and CH3 both on C1 of the ring).

Protonation of -OH → oxonium ion → loss of water → tertiary cyclopentyl carbocation at C1.

Step 2: Ring expansion (1,2-alkyl shift)

The tertiary cyclopentyl carbocation can undergo a ring expansion via 1,2-carbon shift:

  • One of the C-C bonds of the ring migrates to the adjacent carbocation center.
  • This converts the 5-membered ring carbocation into a 6-membered ring carbocation (cyclohexyl carbocation).
  • The cyclohexyl carbocation (secondary or tertiary) is formed — ring expansion is thermodynamically favorable (6-membered ring > 5-membered ring stability).

Step 3: Elimination

The cyclohexyl carbocation loses a proton to give cyclohexene (or methylcyclopentene depending on which proton is lost).

The major product via ring expansion is a cyclohexene derivative.

Key conceptual principle:

Students often miss ring expansion in carbocation intermediates. When a cyclopentane ring carries a carbocation, 1,2-shift of a ring C-C bond to an adjacent cationic C converts 5-membered → 6-membered ring (more stable).

Key Points to Remember:

  • Tertiary carbocations from cyclopentane systems can undergo ring expansion via 1,2-C shift to give cyclohexyl cations.
  • 6-membered ring is more stable than 5-membered → ring expansion is thermodynamically favored.
  • Ring expansion is a key rearrangement to watch for in acid-catalyzed reactions of cyclic alcohols.

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Find out the major product for the following reaction: (JEE Main 2023) | Canvas Classes