For the given compounds, the correct order of increasing pKa value is:
Alcohols, Phenols & Ethers · Class 12 · JEE Main Previous Year Question
For the given compounds, the correct order of increasing value is:
- a
(E) < (D) < (C) < (B) < (A)
- b
(D) < (E) < (C) < (B) < (A)
- c
(E) < (D) < (B) < (A) < (C)
- d✓
(B) < (D) < (A) < (C) < (E)
(B) < (D) < (A) < (C) < (E)
Step 1: Understand pKa and acidity
Lower pKa = stronger acid. Increasing pKa order = increasing in least-to-most acidic order (i.e., decreasing acidity).
Step 2: Effect of substituents on pKa of phenol
- EWG (like -NO2) at ortho/para: stabilizes phenoxide → lowers pKa → more acidic.
- EDG (like -OCH3) at ortho/para: destabilizes phenoxide → raises pKa → less acidic.
- More EWG = lower pKa; more EDG = higher pKa.
Step 3: Rank by pKa (ascending = least acidic to most acidic)
Most acidic (lowest pKa) → least acidic (highest pKa):
- 2,4-Dinitrophenol (2 EWG groups, pKa ≈ 4.0) → most acidic, lowest pKa
- p-Nitrophenol (1 EWG at para, pKa ≈ 7.1)
- Phenol (no substituent, pKa ≈ 10.0)
- p-Methoxyphenol (EDG at para, pKa ≈ 10.2)
- Methoxy-substituted phenol with more EDG (highest pKa, least acidic)
Increasing pKa: B < D < A < C < E
Key Points to Remember:
- EWG at o/p: lowers pKa (more acidic).
- EDG at o/p: raises pKa (less acidic).
- The pKa order is the REVERSE of acidity order.
- 2,4-dinitrophenol: pKa ≈ 4 (nearly as acidic as acetic acid!).
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