In a reaction, reagents X and Y are respectively used to convert salicylic acid: Reagents X and Y are respectively:
Alcohols, Phenols & Ethers · Class 12 · JEE Main Previous Year Question
In a reaction, reagents X and Y are respectively used to convert salicylic acid:
Reagents X and Y are respectively:
- a✓
X = , and Y = , ,
- b
X = , and Y = ,
- c
X = , and Y = ,
- d
X = , , and Y = ,
X = , and Y = , ,
Step 1: Identify X — Salicylic acid → Aspirin
Aspirin = acetylsalicylic acid = the phenolic -OH of salicylic acid is acetylated (not the carboxylic acid -OH).
Acetylation of the phenolic -OH:
Reagent X = acetic anhydride with catalyst ✓
Step 2: Identify Y — Methyl salicylate → Salicylic acid (reverse esterification) OR Salicylic acid → Methyl salicylate
The arrow shows Salicylic acid ←Y— Methyl salicylate, meaning Y converts methyl salicylate back to salicylic acid (hydrolysis). But in synthesis, we prepare methyl salicylate FROM salicylic acid:
Reagent Y = methanol + H+ (acid catalyst), heat — Fischer esterification of the carboxylic acid group ✓
Key distinction: Aspirin synthesis uses acetic anhydride (acetylates -OH phenol); methyl salicylate synthesis uses methanol (esterifies -COOH).
Key Points to Remember:
- Acetic anhydride: acetylates phenolic -OH → aspirin.
- Fischer esterification (ROH + H+): esterifies carboxylic acid → ester.
- Aspirin synthesis: the product contains both -OCOCH3 (phenol ester) and -COOH (free carboxylic acid).
- Aspirin is an analgesic, antipyretic, anti-inflammatory drug.
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