JEE Main · 2023 · Shift-IhardALCO-040

In a reaction, reagents X and Y are respectively used to convert salicylic acid: Reagents X and Y are respectively:

Alcohols, Phenols & Ethers · Class 12 · JEE Main Previous Year Question

Question

In a reaction, reagents X and Y are respectively used to convert salicylic acid: image Reagents X and Y are respectively:

Options
  1. a

    X = (\ceCH3CO)2\ceO(\ce{CH3CO})_2\ce{O}, \ceH+\ce{H^+} and Y = \ceCH3OH\ce{CH3OH}, \ceH+\ce{H^+}, Δ\Delta

  2. b

    X = (\ceCH3CO)2\ceO(\ce{CH3CO})_2\ce{O}, \ceH+\ce{H^+} and Y = (\ceCH3CO)2\ceO(\ce{CH3CO})_2\ce{O}, \ceH+\ce{H+}

  3. c

    X = \ceCH3OH\ce{CH3OH}, \ceH+\ce{H^+} and Y = \ceCH3OH\ce{CH3OH}, \ceH+\ce{H^+}

  4. d

    X = \ceCH3OH\ce{CH3OH}, \ceH+\ce{H^+}, Δ\Delta and Y = (\ceCH3CO)2\ceO(\ce{CH3CO})_2\ce{O}, \ceH+\ce{H^+}

Correct Answera

X = (\ceCH3CO)2\ceO(\ce{CH3CO})_2\ce{O}, \ceH+\ce{H^+} and Y = \ceCH3OH\ce{CH3OH}, \ceH+\ce{H^+}, Δ\Delta

Detailed Solution

Step 1: Identify X — Salicylic acid → Aspirin

Aspirin = acetylsalicylic acid = the phenolic -OH of salicylic acid is acetylated (not the carboxylic acid -OH).

Acetylation of the phenolic -OH: \ceoHOC6H4COOH+(CH3CO)2O>[H+]oCH3COOC6H4COOH+CH3COOH\ce{o-HO-C6H4-COOH + (CH3CO)2O ->[ H+ ] o-CH3COO-C6H4-COOH + CH3COOH}

Reagent X = acetic anhydride (\ceCH3CO)2O(\ce{CH3CO)_2O} with \ceH+\ce{H+} catalyst ✓

Step 2: Identify Y — Methyl salicylate → Salicylic acid (reverse esterification) OR Salicylic acid → Methyl salicylate

The arrow shows Salicylic acid ←Y— Methyl salicylate, meaning Y converts methyl salicylate back to salicylic acid (hydrolysis). But in synthesis, we prepare methyl salicylate FROM salicylic acid:

\ceoHOC6H4COOH+CH3OH<=>[H+][Δ]oHOC6H4COOCH3+H2O\ce{o-HO-C6H4-COOH + CH3OH <=>[H+][\Delta] o-HO-C6H4-COOCH3 + H2O}

Reagent Y = methanol + H+ (acid catalyst), heat — Fischer esterification of the carboxylic acid group ✓

Key distinction: Aspirin synthesis uses acetic anhydride (acetylates -OH phenol); methyl salicylate synthesis uses methanol (esterifies -COOH).

Key Points to Remember:

  • Acetic anhydride: acetylates phenolic -OH → aspirin.
  • Fischer esterification (ROH + H+): esterifies carboxylic acid → ester.
  • Aspirin synthesis: the product contains both -OCOCH3 (phenol ester) and -COOH (free carboxylic acid).
  • Aspirin is an analgesic, antipyretic, anti-inflammatory drug.

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