H3C-CH2-CH(OH)-CH3 (i) NaI, H3PO4; (ii) Mg, dry ether; (iii) D2O Product [X] Product [X] formed in the above reaction…
Alcohols, Phenols & Ethers · Class 12 · JEE Main Previous Year Question
Product [X]
Product [X] formed in the above reaction is:
- a✓
- b
- c
- d
Step 1: Butan-2-ol + NaI/H3PO4 → 2-iodobutane
The -OH is converted to -I (nucleophilic substitution, SN2 with inversion at C2). Product: 2-iodobutane ()
Step 2: 2-Iodobutane + Mg/dry ether → Grignard reagent
The C-I bond is converted to C-MgI (carbanion equivalent). Grignard: sec-butylmagnesium iodide
Step 3: Grignard + D2O → deuterium incorporation
Grignard reagents react with (deuterium oxide) in the same way as with water — the C-Mg bond is protonated/deuterated:
The carbanion equivalent (C-Mg) gets a deuterium from .
Product [X] = (2-deuterobutane) ✓
Key Points to Remember:
- Grignard + → R-D (deuterium incorporation at the carbanion carbon).
- This is used as a synthetic tool to introduce deuterium at specific positions.
- NaI/H3PO4 converts alcohols to iodides (alternative to HI).
- The sequence: alcohol → iodide → Grignard → deuterated compound.
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