Decreasing order of the hydrogen bonding in following forms of water is correctly represented by: A. Liquid water B.…
Chemical Bonding · Class 11 · JEE Main Previous Year Question
Decreasing order of the hydrogen bonding in following forms of water is correctly represented by:
A. Liquid water B. Ice C. Impure water
- a
A = B > C
- b✓
B > A > C
- c
C > B > A
- d
A > B > C
B > A > C
🧠 The number and strength of H bonds per water molecule depends on the order and freedom of the structure. More H bonds per molecule → higher degree of H bonding.
B. Ice: Each forms exactly 4 H bonds in a regular tetrahedral network (2 as donor, 2 as acceptor). This is the maximum possible H bonding per molecule. → Most H bonding
A. Liquid water: Thermal motion disrupts some H bonds (~3.4 H bonds per molecule on average at 25°C). Less ordered than ice. → Intermediate H bonding
C. Impure water: Dissolved solutes (ions, non-polar substances) disrupt the H-bond network by either competing with it or simply occupying space. → Least H bonding
⚡ This explains why ice is less dense than liquid water — the open tetrahedral H-bond lattice in ice takes up more volume than the partially disrupted liquid network.
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