Electronic configuration of four elements A, B, C and D are given below:

(A) $1s^2 2s^2 2p^3$ (B) $1s^2 2s^2 2p^4$ (C) $1s^2 2s^2 2p^5$ (D) $1s^2 2s^2 2p^2$

Which of the following is the correct order of increasing electronegativity (Pauling's scale)?

Question

Electronic configuration of four elements A, B, C and D are given below:

(A) $1s^2 2s^2 2p^3$ (B) $1s^2 2s^2 2p^4$ (C) $1s^2 2s^2 2p^5$ (D) $1s^2 2s^2 2p^2$

Which of the following is the correct order of increasing electronegativity (Pauling's scale)?

Paaras Thakur · Accepted Answer

D < A < B < C. 🧠 Identify the element, then apply the period trend All four configurations are Period 2 elements. Electronegativity increases left to right across a period, so once you know the element, the order follows directly. 🗺️ Identify each (D) 2p2: Carbon (C, Z=6). (A) 2p3: Nitrogen (N, Z=7). (B) 2p4: Oxygen (O, Z=8). (C) 2p5: Fluorine (F, Z=9). Electronegativity increases: C < N < O < F, which means D < A < B < C. {{Answer: (d)}}

Answer

A < D < B < C

Answer

A < C < B < D

Answer

A < B < C < D

Answer

D < A < B < C

Electronic configuration of four elements A, B, C and D are given below: (A) 1s2 2s2 2p3 (B) 1s2 2s2 2p4 (C) 1s2 2s2…

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