JEE Main · 2019 · Shift-IImediumPERI-098

The correct option with respect to the Pauling electronegativity values of the elements is:

Classification of Elements & Periodicity · Class 11 · JEE Main Previous Year Question

Question

The correct option with respect to the Pauling electronegativity values of the elements is:

Options
  1. a

    \ceTe>\ceSe\ce{Te} > \ce{Se}

  2. b

    \ceGa<\ceGe\ce{Ga} < \ce{Ge}

  3. c

    \ceSi<\ceAl\ce{Si} < \ce{Al}

  4. d

    \ceP>\ceS\ce{P} > \ce{S}

Correct Answerb

\ceGa<\ceGe\ce{Ga} < \ce{Ge}

Detailed Solution

🧠 Electronegativity rises left-to-right across a period and drops top-to-bottom in a group — apply both rules to each pair EN follows the same direction as IE for most elements. The Pauling scale is a quick reference, but you can also reason from the trend. image 🗺️ Check each option (a) \ceTe>\ceSe\ce{Te} > \ce{Se}: Both Group 16. Se is above Te. EN drops down a group, so Se > Te, not Te > Se. Wrong. (b) \ceGa<\ceGe\ce{Ga} < \ce{Ge}: Both Period 4. Ge is to the right of Ga. EN rises left-to-right. So Ge > Ga, i.e., Ga < Ge. Correct. Pauling values: Ga = 1.81, Ge = 2.01. (c) \ceSi<\ceAl\ce{Si} < \ce{Al}: Both Period 3. Si is to the right of Al. EN rises left-to-right. So Si > Al, not Si < Al. Wrong. (d) \ceP>\ceS\ce{P} > \ce{S}: Both Period 3. S is to the right of P. EN rises right. So S > P, not P > S. Wrong.

Only option (b) follows the correct trend.

⚠️ The trap Three of the four options invert the obvious "EN rises across a period" rule, hoping students will not notice. Always check the direction of each inequality against the trend before answering. Right side wins in the same period; top wins in the same group. Both habits should become automatic.

Answer: (b)\boxed{\text{Answer: (b)}}

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