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Given below are two statements: Assertion (A): The total number of geometrical isomers shown by [Co(en)2Cl2]+ complex…

Coordination Compounds · Class 12 · JEE Main Previous Year Question

Question

Given below are two statements: Assertion (A): The total number of geometrical isomers shown by [Co(en)2Cl2]+[\mathrm{Co(en)_2Cl_2}]^+ complex ion is three. Reason (R): [Co(en)2Cl2]+[\mathrm{Co(en)_2Cl_2}]^+ complex ion has an octahedral geometry. Choose the most appropriate answer:

Options
  1. a

    Both (A) and (R) are correct but (R) is not the correct explanation of (A)

  2. b

    (A) is not correct but (R) is correct

  3. c

    Both (A) and (R) are correct and (R) is the correct explanation of (A)

  4. d

    (A) is correct but (R) is not correct

Correct Answerb

(A) is not correct but (R) is correct

Detailed Solution

🧠 Geometrical vs Total Stereoisomers

[Co(en)2Cl2]+[\mathrm{Co(en)_2Cl_2}]^+ is octahedral.

  • Geometrical (cis/trans) isomers: 2 (cis + trans).
  • Optical isomers: cis is chiral → 2 enantiomers (Δ-cis, Λ-cis); trans is achiral.
  • Total stereoisomers: 2 (cis-Δ, cis-Λ) + 1 trans = 3.

But the assertion says "total number of geometrical isomers is 3". Geometrical isomers = 2 (cis + trans), not 3. The 3 figure includes the optical pair, which are not geometrical.

So A is incorrect.

Reason says "[Co(en)2Cl2]+[\mathrm{Co(en)_2Cl_2}]^+ has octahedral geometry" — this is correct.

🗺️ Verdict

A wrong, R correct → option (2).

Geometrical vs Stereoisomer Vocabulary

| Term | What it counts | |---|---| | Geometrical isomers | cis/trans (and fac/mer) — positional differences | | Optical isomers | Δ/Λ enantiomers — handedness differences | | Stereoisomers | All of the above combined |

The questions often use "geometrical" loosely to mean "stereoisomer" — read carefully.

⚠️ Don't Lump cis-Δ + cis-Λ + trans = 3 "Geometrical"

cis-Δ and cis-Λ have the same geometric arrangement (both cis); they differ only in chirality. So they count as 1 geometrical isomer (cis), not 2.

Answer: (2) A is not correct but R is correct\boxed{\text{Answer: (2) A is not correct but R is correct}}

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