JEE Main · 2025 · Shift-IhardCORD-246

Number of stereoisomers possible for the complexes, [CrCl3(py)3] and [CrCl3(ox)2]3- are respectively (py = pyridine, ox…

Coordination Compounds · Class 12 · JEE Main Previous Year Question

Question

Number of stereoisomers possible for the complexes, [\ceCrCl3(py)3][\ce{CrCl3(py)3}] and [\ceCrCl3(ox)2]3[\ce{CrCl3(ox)2}]^{3-} are respectively

(pypy = pyridine, oxox = oxalate)

Options
  1. a

    33 & 33

  2. b

    22 & 22

  3. c

    22 & 33

  4. d

    11 & 22

Correct Answerc

22 & 33

Detailed Solution

🧠 Compute Stereoisomer Counts

Stereoisomer = geometric + optical (enantiomers count separately).

🗺️ (a) [CrCl3(py)3][\mathrm{CrCl_3(py)_3}] — Type MA3B3MA_3 B_3

Octahedral MA3B3MA_3 B_3fac (3 like ligands on one face) and mer (3 like ligands on a meridian).

Both fac and mer are achiral (each has a mirror plane).

Stereoisomer count = 2.

🗺️ (b) [CrCl2(ox)2]3[\mathrm{CrCl_2(ox)_2}]^{3-} — Type [M(AA)2B2][M(AA)_2 B_2]

(Note: the formula in the question is keyed as 3 Cl + 2 ox, which exceeds 6 donors; the chemistry-consistent reading is [CrCl2(ox)2]3[\mathrm{CrCl_2(ox)_2}]^{3-}, type [M(AA)2B2][M(AA)_2 B_2].)

  • trans isomer: Cl axial-axial (180°), achiral. Count = 1.
  • cis isomer: Cl cis (90°), chiral → 2 enantiomers (Δ, Λ). Count = 2.

Stereoisomer count = 1+2=1 + 2 = 3.

🗺️ Final

(a) 2 ; (b) 3.

Stereoisomer Counting Summary

| Type | Geometric | Optical | Total stereoisomers | |---|---|---|---| | MA3B3MA_3 B_3 (oct) | fac, mer | none | 2 | | M(AA)2X2M(AA)_2 X_2 (oct) | cis (chiral), trans | cis Δ/Λ | 3 | | M(AA)3M(AA)_3 | one form | Δ/Λ | 2 |

⚠️ cis-M(AA)2X2M(AA)_2 X_2 Counted as Δ + Λ

cis form is chiral, contributing 2 enantiomers. trans is achiral, contributing 1. Total = 3.

Answer: (3) 2 and 3\boxed{\text{Answer: (3) 2 and 3}}

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