Given below are two statements: Statement I: A homoleptic octahedral complex, formed using monodentate ligands, will…
Coordination Compounds · Class 12 · JEE Main Previous Year Question
Given below are two statements:
Statement I: A homoleptic octahedral complex, formed using monodentate ligands, will not show stereoisomerism.
Statement II: cis- and trans- platin are heteroleptic complexes of Pd.
In the light of the above statements, choose the correct answer from the options given below:
- a
Both statement I and Statement II are false.
- b
Statement I is false but Statement II is true.
- c
Both statement I and Statement II are true.
- d✓
Statement I is true but Statement II is false.
Statement I is true but Statement II is false.
🧠 Two Statements to Verify
🗺️ Statement I: Homoleptic Octahedral Monodentate → No Stereoisomerism
A homoleptic complex has all 6 ligands identical. In octahedral :
- Type has only one possible arrangement — all 6 corners equivalent.
- No cis/trans, no fac/mer, no chirality possible.
→ Statement I is TRUE.
🗺️ Statement II: cis- and trans-platin Are Heteroleptic Complexes of Pd
cis-platin = - (anticancer drug). trans-platin = trans isomer.
These are complexes of Pt (platinum), not Pd (palladium). Both are heteroleptic ✓ but the metal identification is wrong.
→ Statement II is FALSE (because of Pt vs Pd error).
⚡ Pt(II) Square Planar — Anticancer
cis- binds DNA, blocking replication; the trans isomer is biologically inactive due to wrong geometry.
⚠️ Don't Confuse Pt with Pd
Pt and Pd are both d⁸ Group 10 metals giving sq pl(II) complexes, but they are different elements. Always read carefully.
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