JEE Main · 2021 · Shift-IeasyHC-016

Identify A in the given chemical reaction.

Hydrocarbons · Class 11 · JEE Main Previous Year Question

Question

Identify A in the given chemical reaction. image image

Options
  1. a

    Option a

  2. b

    Option b

  3. c

    Option c

  4. d

    Option d

Correct Answera

Option a

Detailed Solution

Step 1: Identify the reaction type

The reaction involves \ceMo2O3\ce{Mo2O3} (or similar aromatization catalyst) acting on a cyclic hydrocarbon. \ceMo2O3\ce{Mo2O3} is an aromatization reagent that converts cyclohexane derivatives to aromatic compounds by dehydrogenation.

Step 2: Trace the reaction

The reaction sequence converts compound A (an aromatic compound) back from its precursor:

  • \ceMo2O3\ce{Mo2O3} promotes aromatization: cyclohexane → benzene, methylcyclohexane → toluene
  • The reaction involves oxidative dehydrogenation

Step 3: Identify A

Given that the product involves the aromatic ring with a methyl substituent, compound A = Toluene (\ceC6H5CH3\ce{C6H5CH3}).

The reaction is: methylcyclohexane \ceMo2O3\xrightarrow{\ce{Mo2O3}} toluene + \ce3H2\ce{3H2}

Working backwards: A (toluene) is the aromatic product.

Answer: Option (a) — Toluene

Key Points to Remember:

  • \ceMo2O3\ce{Mo2O3} is an aromatization catalyst (dehydrogenation)
  • Cyclohexane → Benzene (aromatization): loses 3 \ceH2\ce{H2}
  • Methylcyclohexane → Toluene: loses 3 \ceH2\ce{H2}
  • This reaction is important in catalytic reforming of petroleum

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