JEE Main · 2020 · Shift-IImediumMOLE-206

The NH3 released on quantitative reaction of 0.6 g urea (NH2CONH2, MW=60) with NaOH can be neutralized by:

Some Basic Concepts (Mole Concept) · Class 11 · JEE Main Previous Year Question

Question

The \ceNH3\ce{NH3} released on quantitative reaction of 0.6 g urea (\ceNH2CONH2\ce{NH2CONH2}, MW=60) with NaOH can be neutralized by:

Options
  1. a

    200 mL of 0.4 N HCl

    ✓
  2. b

    200 mL of 0.2 N HCl

  3. c

    100 mL of 0.2 N HCl

  4. d

    100 mL of 0.1 N HCl

Correct Answera

200 mL of 0.4 N HCl

Detailed Solution

🧠 The Urea "Double-Ammonia" Rule One mole of Urea (60 g60\,g) contains two Nitrogen atoms. When you treat it with NaOH (or use the enzyme urease), it releases 2 moles of Ammonia. This doubling effect is the most common place students lose marks.

🗺️ Strategic Roadmap Step 1: Identify the Ammonia Reservoir. Urea: 0.6/60=0.01 mol0.6 / 60 = 0.01\,mol. Released \ceNH3=0.01×2=0.02 mol\ce{NH3} = 0.01 \times 2 = 0.02\,mol.

Step 2: Neutralization Match. Reaction: \ceNH3+HCl→NH4Cl\ce{NH3 + HCl \rightarrow NH4Cl}. Need exactly 0.020.02 equivalents (molesmoles) of HCl.

  • Option (a): 200 mL×0.4 N=0.08200\,mL \times 0.4\,N = 0.08 eq. (Wrong)
  • Option (c): 100 mL×0.2 N=0.02100\,mL \times 0.2\,N = 0.02 eq. (MATCH)

Answer: (c) 100 mL of 0.2 N HCl\boxed{\text{Answer: (c) 100 mL of 0.2 N HCl}}

Practice this question with progress tracking

Want timed practice with adaptive difficulty? Solve this question (and hundreds more from Some Basic Concepts (Mole Concept)) inside The Crucible, our adaptive practice platform.

Practice in The Crucible →Browse Some Basic Concepts (Mole Concept) chapter →

More JEE Main Some Basic Concepts (Mole Concept) PYQs

2025hard

CaCO3(s) + 2HCl(aq) - CaCl2(aq) + CO2(g) + H2O(l) What mass of CaCl2 will be formed if 250 mL of 0.76 M HCl reacts with 1000 g of CaCO3? (Given: Molar mass of Ca, C, O, H and Cl are 40, 12, 16, 1 and…

2025medium

Which of the following linear combination of atomic orbitals will lead to formation of molecular orbitals in homonuclear diatomic molecules (internuclear axis in z-direction)? A. 2pz and 2px B. 2s…

2024easy

The number of moles of methane required to produce 11\,g of CO2(g) after complete combustion is: (Molar mass of methane = 16\,g/mol)

2024easy

Combustion of glucose (C6H12O6) produces CO2 and water. The amount of oxygen (in g) required for complete combustion of 900\,g of glucose is: [Molar mass of glucose = 180\,g/mol]

2024hard

A sample of CaCO3 and MgCO3 weighed 2.21\,g is ignited to constant weight of 1.152\,g. The composition of the mixture is: (Mr: CaCO3=100, MgCO3=84)

View all 57 Some Basic Concepts (Mole Concept) PYQs →
The NH3 released on quantitative reaction of 0.6 g urea (NH2CONH2, MW=60) with NaOH can be… (JEE Main 2020) | Canvas Classes