JEE Main · 2022 · Shift-ImediumPB11-061

Borazine, also known as inorganic benzene, can be prepared by the reaction of 3-equivalents of "X" with 6 equivalents…

p-Block Elements (Class 11) · Class 11 · JEE Main Previous Year Question

Question

Borazine, also known as inorganic benzene, can be prepared by the reaction of 3-equivalents of "X" with 6 equivalents of "Y". "X" and "Y", respectively are

Options
  1. a

    B(OH)3\mathrm{B(OH)_3} and NH3\mathrm{NH_3}

  2. b

    B2H6\mathrm{B_2H_6} and NH3\mathrm{NH_3}

  3. c

    B2H6\mathrm{B_2H_6} and HN3\mathrm{HN_3}

  4. d

    NH3\mathrm{NH_3} and B2O3\mathrm{B_2O_3}

Correct Answerb

B2H6\mathrm{B_2H_6} and NH3\mathrm{NH_3}

Detailed Solution

Strategy: Identify X and Y in the synthesis of Borazine (\ceB3N3H6\ce{B3N3H6}) from 3 equivalents of X and 6 equivalents of Y.

Step 1: Borazine Synthesis Reaction Borazine (inorganic benzene, \ceB3N3H6\ce{B3N3H6}) is synthesised by: \ce3B2H6+6NH3>[ 450K ]2B3N3H6+12H2\ce{3B2H6 + 6NH3 ->[\ 450K\ ] 2B3N3H6 + 12H2}

Step 2: Identifying X and Y The question states: "3 equivalents of X with 6 equivalents of Y"

  • 3 equivalents of \ceB2H6\ce{B2H6} (diborane) = X
  • 6 equivalents of \ceNH3\ce{NH3} (ammonia) = Y

Answer: (B) X = \ceB2H6 and Y = \ceNH3\boxed{\text{Answer: (B) X = }\ce{B2H6}\text{ and Y = }\ce{NH3}}

Practice this question with progress tracking

Want timed practice with adaptive difficulty? Solve this question (and hundreds more from p-Block Elements (Class 11)) inside The Crucible, our adaptive practice platform.

Borazine, also known as inorganic benzene, can be prepared by the reaction of 3-equivalents of "X"… (JEE Main 2022) | Canvas Classes