JEE Main · 2019 · Shift-IeasyPB11-033

Diborane (B2H6) reacts independently with O2 and H2O to produce, respectively:

p-Block Elements (Class 11) · Class 11 · JEE Main Previous Year Question

Question

Diborane (B2H6\mathrm{B_2H_6}) reacts independently with O2\mathrm{O_2} and H2O\mathrm{H_2O} to produce, respectively:

Options
  1. a

    HBO2\mathrm{HBO_2} and H3BO3\mathrm{H_3BO_3}

  2. b

    H3BO3\mathrm{H_3BO_3} and B2O3\mathrm{B_2O_3}

  3. c

    B2O3\mathrm{B_2O_3} and [BH4][\mathrm{BH_4}]^-

  4. d

    B2O3\mathrm{B_2O_3} and H3BO3\mathrm{H_3BO_3}

Correct Answerd

B2O3\mathrm{B_2O_3} and H3BO3\mathrm{H_3BO_3}

Detailed Solution

Strategy: Determine the products when diborane reacts separately with \ceO2\ce{O2} and \ceH2O\ce{H2O}.

Step 1: Reaction with O₂ (Oxidation) \ceB2H6+3O2>B2O3+3H2O\ce{B2H6 + 3O2 -> B2O3 + 3H2O} Product: \ceB2O3\ce{B2O3} (diboron trioxide / boron(III) oxide).

Step 2: Reaction with H₂O (Hydrolysis) \ceB2H6+6H2O>2H3BO3+6H2\ce{B2H6 + 6H2O -> 2H3BO3 + 6H2} Product: \ceH3BO3\ce{H3BO3} (orthoboric acid) + hydrogen gas.

Summary: With \ceO2\ce{O2}\ceB2O3\ce{B2O3}; With \ceH2O\ce{H2O}\ceH3BO3\ce{H3BO3}

Answer: (D) \ceB2O3 and \ceH3BO3\boxed{\text{Answer: (D) }\ce{B2O3}\text{ and }\ce{H3BO3}}

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