JEE Main · 2025 · Shift-IImediumPB12-128

The amphoteric oxide among V2O3, V2O4 and V2O5 upon reaction with alkali leads to formation of an oxide anion. The…

p-Block Elements (Class 12) · Class 12 · JEE Main Previous Year Question

Question

The amphoteric oxide among V2O3\text{V}_2\text{O}_3, V2O4\text{V}_2\text{O}_4 and V2O5\text{V}_2\text{O}_5 upon reaction with alkali leads to formation of an oxide anion. The oxidation state of V in the oxide anion is:

(a) +3+3 \quad (b) +7+7 \quad (c) +5+5 \quad (d) +4+4

Options
  1. a

    +3+3

  2. b

    +7+7

  3. c

    +5+5

  4. d

    +4+4

Correct Answerc

+5+5

Detailed Solution

Step 1 — Identify amphoteric oxide:

V2O5\text{V}_2\text{O}_5 is amphoteric; reacts with alkali:

V2O5+6NaOH2Na3VO4+3H2O\text{V}_2\text{O}_5 + 6\text{NaOH} \rightarrow 2\text{Na}_3\text{VO}_4 + 3\text{H}_2\text{O}

Oxide anion formed: VO43\text{VO}_4^{3-}

Step 2 — Oxidation state of V in VO43\text{VO}_4^{3-}:

x+4(2)=3    x=+5x + 4(-2) = -3 \implies x = +5

Answer: (c) +5+5

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