JEE Main · 2024 · Shift-IIeasySOL-004

If a substance 'A' dissolves in solution of a mixture of 'B' and 'C' with their respective number of moles as nA, nB…

Solutions · Class 12 · JEE Main Previous Year Question

Question

If a substance 'A' dissolves in solution of a mixture of 'B' and 'C' with their respective number of moles as nAn_A, nBn_B and nCn_C, mole fraction of C in the solution is:

Options
  1. a

    nCnA×nB×nC\frac{n_C}{n_A \times n_B \times n_C}

  2. b

    nCnA+nB+nC\frac{n_C}{n_A + n_B + n_C}

  3. c

    nCnAnBnC\frac{n_C}{n_A - n_B - n_C}

  4. d

    nBnA+nB\frac{n_B}{n_A + n_B}

Correct Answerb

nCnA+nB+nC\frac{n_C}{n_A + n_B + n_C}

Detailed Solution

Strategy:\n> Mole fraction (xix_i) is the ratio of the number of moles of a specific component to the total number of moles of all species in the mixture.\n\nStep 1: Calculate total moles\nTotal moles (ntexttotal)=nA+nB+nC(n_{\\text{total}}) = n_A + n_B + n_C\n\nStep 2: Apply mole fraction definition for C\nxC=fracnCnA+nB+nCx_C = \\frac{n_C}{n_A + n_B + n_C}\n\ntextAnswer:(2)\boxed{\\text{Answer: (2)}}

Practice this question with progress tracking

Want timed practice with adaptive difficulty? Solve this question (and hundreds more from Solutions) inside The Crucible, our adaptive practice platform.

If a substance 'A' dissolves in solution of a mixture of 'B' and 'C' with their respective number… (JEE Main 2024) | Canvas Classes