What is the mass ratio of ethylene glycol (C2H6O2, molar mass = 62 g/mol) required for making 500 g of 0.25 molal…
Solutions · Class 12 · JEE Main Previous Year Question
What is the mass ratio of ethylene glycol (, molar mass = 62 g/mol) required for making 500 g of 0.25 molal aqueous solution and 250 mL of 0.25 molar aqueous solution?
- a
1 : 1
- b
3 : 1
- c✓
2 : 1
- d
1 : 2
2 : 1
Strategy:\n> Calculate the moles of ethylene glycol required for each solution and compare them.\n\nStep 1: Calculate moles for 500 g of 0.25 molal solution\nMolality () . Solvent mass (assuming dilute solution).\n\n\nStep 2: Calculate moles for 250 mL of 0.25 molar solution\nMolarity () . Volume .\n\n\nStep 3: Determine mass ratio\nRatio .\n\n
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