What is the mass ratio of ethylene glycol (C2H6O2, molar mass = 62 g/mol) required for making 500 g of 0.25 molal…

Strategy:\n> Calculate the moles of ethylene glycol required for each solution and compare them.\n\nStep 1: Calculate moles for 500 g of 0.25 molal solution\nMolality ($m$) $= 0.25$. Solvent mass $\approx 500\\text{ g} = 0.5\\text{ kg}$ (assuming dilute solution).\n$n_1 = m \\times 0.5 = 0.25 \\times 0.5 = 0.125\\text{ mol}$\n\nStep 2: Calculate moles for 250 mL of 0.25 molar solution\nMolarity ($M$) $= 0.25$. Volume $= 0.25\\text{ L}$.\n$n_2 = M \\times 0.25 = 0.25 \\times 0.25 = 0.0625\\text{ mol}$\n\nStep 3: Determine mass ratio\nRatio $= n_1 : n_2 = 0.125 : 0.0625 = 2 : 1$.\n\n$\boxed{\\text{Answer: (3)}}$