The Molarity (M) of an aqueous solution containing 5.85 g of NaCl in 500 mL water is: (Given: Molar Mass Na: 23 and Cl:…
Solutions · Class 12 · JEE Main Previous Year Question
The Molarity (M) of an aqueous solution containing 5.85 g of NaCl in 500 mL water is:
(Given: Molar Mass Na: 23 and Cl: 35.5 g mol⁻¹)
- a
2
- b
20
- c
4
- d✓
0.2
0.2
Strategy:\n> Molarity () is a concentration term that defines the number of moles of solute present in exactly one liter of a solution. Calculate the moles of and divide by the volume in liters.\n\nStep 1: Calculate the molar mass of } \ce{NaCl} \text{\n- Atomic mass of \n- Atomic mass of \n- Molar mass \n\nStep 2: Determine moles of } \ce{NaCl} \text{\n\n\nStep 3: Calculate Molarity ()\nVolume = 500 mL = 0.5 L.\n\n\n
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