Ch. 1 | Some Basic Concepts of Chemistry0/14

Laws of Chemical Combinations

Before atoms were proven to exist, scientists discovered the rules governing how elements combine — rules that still hold true today.

Rules Before the Atom

Lavoisier, Proust and Dalton worked out the laws of chemical combination in the late 1700s — before anyone had ever seen an atom. They did it by carefully weighing what went into a reaction and what came out. These laws are the bedrock of stoichiometry — the quantitative study of chemistry.

Stoichiometry describes the quantitative relationships that exist between substances undergoing chemical changes. The word comes from Greek: stoicheion (element) + metron (measure).

It is built on five foundational laws of chemical combination:

  1. Law of Conservation of Mass
  2. Law of Definite Proportions
  3. Law of Multiple Proportions
  4. Law of Reciprocal Proportions
  5. Gay Lussac's Law of Gaseous Volumes

Avogadro's Law is closely related and ties gaseous volumes to molecules.

Law of Conservation of Mass

Lavoisier (1744) stated: "Matter can neither be created nor destroyed during any chemical or physical change; however, its physical or chemical nature may change."

In simple terms: the total mass of reactants = total mass of products.

Examples:

  • Ice \rightarrow Water: 20 g of ice gives exactly 20 g of water
  • HX2(g)+12OX2(g)HX2O(l)\ce{H2(g) + \frac{1}{2}O2(g) -> H2O(l)}: 2 g + 16 g \rightarrow 18 g
  • HX2+ClX22HCl\ce{H2 + Cl2 -> 2HCl}: 2 g + 71 g \rightarrow 73 g

Exception: In nuclear reactions, some mass is converted into energy as per E=mc2E = mc^2.

Law of Definite Proportions

Proust (1799) stated: "A chemical compound, irrespective of the source from which it is obtained, always contains the same elements combining in definite ratios by mass."

Examples:

  • HX2O\ce{H2O} from a river, pond, or rain — H and O are always in a 1:8 ratio by mass
  • COX2\ce{CO2} formed by burning carbon or decomposing limestone — C and O always in a 3:8 ratio by mass (i.e., 12 g C + 32 g O = 44 g COX2\ce{CO2})

Exceptions: Isotopes and non-stoichiometric compounds.

  • HX2X16X2216O\ce{H2^{16}O} has H:O = 1:8, but HX2X18X2218O\ce{H2^{18}O} has H:O = 1:9 (due to heavier oxygen isotope)
  • FeX0.95O\ce{Fe_{0.95}O} is a non-stoichiometric compound containing a mixture of FeX2+\ce{Fe^{2+}} and FeX3+\ce{Fe^{3+}} ions
Solved ExampleLaw of Definite Proportions (Copper Oxide)
SOLVED

Heating 2.162.16 g of metallic copper with nitric acid and igniting it gave 2.72.7 g of copper oxide. In another experiment, 1.151.15 g of copper oxide on reduction yielded 0.920.92 g of copper. Show that these results illustrate the law of definite proportions.

Law of Multiple Proportions

Dalton stated: "When two elements combine with each other to form two or more compounds, then the different amounts of one element which react with a definite amount of the second element are in a simple whole number ratio."

Classic example — nitrogen and oxygen form five different oxides:

OxideMass of N (g)Mass of O (g)
NX2O\ce{N2O}2816
NO\ce{NO}2832
NX2OX3\ce{N2O3}2848
NX2OX4\ce{N2O4}2864
NX2OX5\ce{N2O5}2880

The masses of oxygen combining with a fixed 28 g of nitrogen are: 16 : 32 : 48 : 64 : 80 = 1 : 2 : 3 : 4 : 5 — a simple whole number ratio. ✓

Another example: CO and COX2\ce{CO2} both contain C and O. In CO, C:O = 12:16. In COX2\ce{CO2}, C:O = 12:32. For a fixed 12 g of carbon, oxygen masses are 16 g and 32 g → ratio 1:2.

Solved ExampleLaw of Multiple Proportions
SOLVED

A and B combine to form four compounds P, Q, R and S:

  • 0.60.6 g A + 0.8+\ 0.8 g B 1.4\rightarrow 1.4 g P
  • 9.09.0 g A + 24.0+\ 24.0 g B 33.0\rightarrow 33.0 g Q
  • 4040 g A + 160+\ 160 g B 200\rightarrow 200 g R
  • 1818 g A + 93.6+\ 93.6 g B 111.6\rightarrow 111.6 g S

Show that these data obey the law of multiple proportions.

Law of Reciprocal Proportions

Richter stated: when two different elements each combine separately with a fixed mass of a third element, the ratio of their two masses is the same as — or a simple multiple of — the ratio in which those two elements combine directly with each other.

Take hydrogen, oxygen and sulphur:

  • In HX2O\ce{H2O}, 1 g of hydrogen combines with 8 g of oxygen.
  • In HX2S\ce{H2S}, 1 g of hydrogen combines with 16 g of sulphur.
  • So, measured against the same 1 g of hydrogen, oxygen and sulphur stand in the ratio 8 : 16 = 1 : 2.

Now let sulphur and oxygen combine directly: in SOX2\ce{SO2} they react as 32 g : 32 g = 1 : 1. The law predicts that direct ratio should be 1 : 2 or a simple multiple of it, and 1 : 1 is exactly that (a 2× multiple). The prediction holds — without anyone ever weighing a single atom.

Gay Lussac's Law & Avogadro's Law

Gay Lussac's Law of Gaseous Volumes: In a gaseous reaction, the reactants combine in simple ratios by volume, and the products are also formed in simple ratios by volume — at the same temperature and pressure.

Examples:

  • HX2(g)+ClX2(g)2HCl(g)\ce{H2(g) + Cl2(g) -> 2HCl(g)}: 1 L + 1 L \rightarrow 2 L (ratio 1:1:2)
  • NX2+3HX22NHX3\ce{N2 + 3H2 -> 2NH3}: 1 L + 3 L \rightarrow 2 L (ratio 1:3:2)

This law applies only to gaseous reactions. It relates volume to moles or molecules — NOT directly to mass.

Avogadro's Law: Equal volumes of all gases contain equal number of molecules at the same temperature and pressure.

PV=nRTn=PVRTPV = nRT \quad \Rightarrow \quad n = \frac{PV}{RT}

If V, P, and T are the same for two gas containers, then nn (number of moles / molecules) must also be the same — regardless of which gas is inside.

Fig. 1.13The five laws of chemical combination — the foundation of stoichiometry
Solved ExampleLaw of Combining Volumes (H₂ + Cl₂)
SOLVED

For HX2(g)+ClX2(g)2HCl(g)\ce{H2(g) + Cl2(g) -> 2HCl(g)}: if 4040 mL of HX2\ce{H2} reacts completely with ClX2\ce{Cl2}, find the volume of ClX2\ce{Cl2} required and the volume of HCl\ce{HCl} produced (same temperature and pressure).

Solved ExampleReacting Gas Volumes (CO + O₂)
SOLVED

1010 L of CO\ce{CO} and 1010 L of OX2\ce{O2} are allowed to react to the maximum possible extent at the same temperature and pressure. For CO+12OX2COX2\ce{CO + 1/2 O2 -> CO2}, calculate the final volume of the reaction mixture.

Solved ExampleAvogadro's Law (Ratio of Atoms)
SOLVED

Four 1 L flasks are separately filled with SOX2\ce{SO2}, SOX3\ce{SO3}, Ar and CHX4\ce{CH4} at the same temperature and pressure. What is the ratio of the total number of atoms of these gases in the different flasks?

JEE / NEET Exam InsightJEE / NEET
Conservation of Mass in reactions: Total mass of reactants = total mass of products. If a reaction appears to lose mass (e.g., gas escapes), the system is open — the gas must be accounted for.
Law of Definite Proportions — exam trap: Isotopes violate this law. HX2X16X2216O\ce{H2^{16}O} and HX2X18X2218O\ce{H2^{18}O} are both 'water' but have different H:O mass ratios. Non-stoichiometric compounds like FeX0.95O\ce{Fe_{0.95}O} also violate it.
Gay Lussac's Law applies only to gases. It cannot be applied to reactions involving solids or liquids — a common mistake.
Avogadro's Law and number of atoms: Equal volumes of SOX2\ce{SO2} and CHX4\ce{CH4} at same T & P have equal molecules, but different numbers of atoms (SO2 has 3 atoms/molecule, CH4 has 5). Ratio of atoms = 3:5, not 1:1.
Reciprocal Proportions (Richter): If A combines with B (ratio x:yx:y) and A combines with C (ratio x:zx:z), then when B and C combine with each other, the ratio is y:zy:z or a simple multiple of it.
Quick Check

Q1.3.4 g of AgNO₃ in 100 g water reacts with 1.17 g of NaCl in 100 g water to give 2.87 g AgCl and 1.70 g NaNO₃. Which law does this data verify?