Ch. 1 | Some Basic Concepts of Chemistry0/12

The Mole Concept

Avogadro's number is the chemist's counting unit — like a dozen, but 50 billion times larger.

Why We Need a 'Dozen' for Atoms

You can't go to a shop and ask for '3 atoms of carbon'. Atoms are too small. But if you could count out 6.022×10236.022 \times 10^{23} carbon atoms, you'd have exactly 12 grams — a workable, measurable quantity. That's the genius of the mole: it's a bridge between the invisible world of atoms and the grams-and-litres world of the laboratory.

Why we measure some things by mass, and others by counting.

Stop and notice how we measure quantities in everyday life. Some things we weigh. Some things we count. The choice isn’t random — it depends on the object.

  • Apples vary in size and weight, so we measure them by mass: one kilo of apples, not “ten apples.”
  • Bananas also vary in size, but they’re easy to grab and count. So we measure them by number: a dozen bananas.
  • Grains of rice or wheat are nearly identical in size — but there are thousands in a single fistful. Counting is hopeless. So we measure them by mass: one kilo of rice.
  • Potatoes — count, like apples. Five potatoes.

The pattern: if there are too many to count, or sizes vary, we weigh. If we can grab and count, we count.

In a chemistry lab, you face the same dilemma — but at an extreme. When two substances react, they react one atom at a time. So you want to know how many atoms or molecules of each substance you have. But there are billions of trillions of atoms in even a single grain of salt. Counting them is impossible.

The mole is the unit chemists invented to solve exactly this problem. It lets you count by weighing — you measure mass on a scale, and instantly know how many particles you’re holding.

The Mole — Definition

A mole is the amount of substance that contains as many entities (atoms, molecules, ions, or other particles) as there are atoms in exactly 12 g of the X12X2212C\ce{^{12}C} isotope.

This number was determined experimentally using a mass spectrometer. The mass of one X12X2212C\ce{^{12}C} atom was found to be 1.992648×10231.992648 \times 10^{-23} g. Therefore:

NA=12 g/mol1.992648×1023 g=6.022×1023 mol1N_A = \frac{12 \text{ g/mol}}{1.992648 \times 10^{-23} \text{ g}} = 6.022 \times 10^{23} \text{ mol}^{-1}

This is Avogadro's constant (NAN_A):

NA=6.022×1023 entities per moleN_A = 6.022 \times 10^{23} \text{ entities per mole}

Just like 1 dozen = 12, 1 mole = 6.022×10236.022 \times 10^{23}. It's simply a counting number — a convenient-sized chunk of atoms.

  • 1 gram-atom = 1 mole of atoms = 6.022×10236.022 \times 10^{23} atoms
  • 1 gram-molecule = 1 mole of molecules = 6.022×10236.022 \times 10^{23} molecules

How big is Avogadro’s number, really?

602,200,000,000,000,000,000,000. Twenty-three zeros. It’s hard to grasp how big that is — so here are three known-large quantities for scale:

ChatGPT Image May 28, 2026, 05_16_41 PM

Molar Mass & Molar Volume

Molar mass is the mass of 1 mole of a substance, expressed in g/mol. Numerically, it equals the atomic or molecular mass in u:

Substance1 mole weighs
X12X2212C\ce{^{12}C}12 g
X16X2216O\ce{^{16}O}16 g
N\ce{N}14 g
HX2O\ce{H2O}18 g
NaCl\ce{NaCl}58.5 g

So if the atomic mass of Fe is 56 u, then 1 mole of Fe atoms = 56 g.

Molar Volume is the volume occupied by 1 mole of any gas at a given temperature and pressure.

At STP (Standard Temperature and Pressure: 0 °C, 1 atm):
Molar volume of any gas=22.4 L=22400 mL\text{Molar volume of any gas} = 22.4 \text{ L} = 22400 \text{ mL}

This is the same for ALL gases — HX2\ce{H2}, OX2\ce{O2}, COX2\ce{CO2}, NHX3\ce{NH3} — at STP, 1 mole of any gas occupies 22.4 L.

The Master Formula — Calculating Moles

The number of moles (nn) can be calculated three different ways depending on what information is given:

n=Given massMolar mass=wMn = \frac{\text{Given mass}}{\text{Molar mass}} = \frac{w}{M}

n=Number of particlesNA=N6.022×1023n = \frac{\text{Number of particles}}{N_A} = \frac{N}{6.022 \times 10^{23}}

n=Volume at STP (L)22.4n = \frac{\text{Volume at STP (L)}}{22.4}

These three expressions are equivalent — use whichever one matches the information given in the problem.

Key conversions:

  • Mass of 1 atom = Atomic massNA\frac{\text{Atomic mass}}{N_A} g
  • Mass of 1 molecule = Molecular massNA\frac{\text{Molecular mass}}{N_A} g
  • Number of atoms = n×NAn \times N_A
  • Number of molecules = n×NAn \times N_A
n=wM=NNA=VSTP22.4 Ln = \frac{w}{M} = \frac{N}{N_A} = \frac{V_{\text{STP}}}{22.4 \text{ L}}

The Mole Triad

n = moles, w = given mass (g), M = molar mass (g/mol), N = number of particles, NA = 6.022 × 10²³, V(STP) = volume at STP in litres

Mole concept triangle diagram showing three routes to calculate moles
📸 The mole triad — three ways to calculate moles from mass, particles, or volume

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Example 1
NCERT

A piece of copper weighs 0.635 g. How many atoms of copper does it contain? (Atomic mass of Cu = 63.5 u)

Example 2
NCERT

Calculate the number of molecules in 11.2 L of SOX2\ce{SO2} gas at STP.

Example 3From molecules to mass
SOLVED

Calculate the weight of 6.022×10246.022 \times 10^{24} molecules of CaCOX3\ce{CaCO3}.

Atomic masses: Ca = 40, C = 12, O = 16

Example 4Counting atoms in polyatomic molecules
SOLVED

How many atoms are present in 12.044×102312.044 \times 10^{23} molecules of CHX4\ce{CH4}?

JEE / NEET Exam InsightJEE / NEET
Molar mass = atomic/molecular mass in grams: If the atomic mass of Na is 23 u, then 1 mole of Na = 23 g. This simple link between u and g/mol is the most-used fact in all of stoichiometry.
22.4 L applies only at STP (0 °C, 1 atm). Many problems trick you by specifying a different temperature. If the temperature is not 0 °C, use PV=nRTPV = nRT instead.
Counting atoms vs molecules: 1 mole of OX2\ce{O2} contains NAN_A molecules but 2NA2N_A atoms. Always check whether the question asks for atoms or molecules.
Mass of one atom: = Atomic mass / NAN_A = M6.022×1023\frac{M}{6.022 \times 10^{23}} g. This is a direct calculation JEE often tests.
Useful number relations:
    1 mole of HX2O\ce{H2O} (18 g) → NAN_A molecules → 3NA3N_A atoms → 10NA10N_A electrons
    1 mole of NaCl\ce{NaCl}NAN_A formula units → NAN_A NaX+\ce{Na^+} ions + NAN_A ClX\ce{Cl^-} ions
Quick Check

Q1.How many moles of NH₃ are present in 5.6 L of NH₃(g) at STP?