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The complex that can show optical activity is:

Coordination Compounds · Class 12 · JEE Main Previous Year Question

Question

The complex that can show optical activity is:

Options
  1. a

    trans-[Cr(Cl2)(ox)2]3[\mathrm{Cr(Cl_2)(ox)_2}]^{3-}

  2. b

    trans-[Fe(NH3)2(CN)4][\mathrm{Fe(NH_3)_2(CN)_4}]^-

  3. c

    cis-[Fe(NH3)2(CN)4][\mathrm{Fe(NH_3)_2(CN)_4}]^-

  4. d

    cis-[CrCl2(ox)2]3[\mathrm{CrCl_2(ox)_2}]^{3-} (ox = oxalate)

Correct Answerd

cis-[CrCl2(ox)2]3[\mathrm{CrCl_2(ox)_2}]^{3-} (ox = oxalate)

Detailed Solution

🧠 Look for Lack of Mirror Symmetry

A complex is optically active if it has no mirror plane, no centre of inversion, no improper axis. cis-bisbidentate octahedrals with two extra ligands are the classic chiral motif.

🗺️ Evaluate Each

| Complex | Symmetry | Optical activity | |---|---|---| | trans-[CrCl2(ox)2]3[\mathrm{CrCl_2(ox)_2}]^{3-} | Has σh\sigma_h plane | ✗ achiral | | trans-[Fe(NH3)2(CN)4][\mathrm{Fe(NH_3)_2(CN)_4}]^- | Has σ\sigma planes (D4hD_{4h}) | ✗ achiral | | cis-[Fe(NH3)2(CN)4][\mathrm{Fe(NH_3)_2(CN)_4}]^- | Has σ\sigma plane through CN ligands | ✗ achiral | | cis-[CrCl2(ox)2]3[\mathrm{CrCl_2(ox)_2}]^{3-} | C2C_2 only, no mirror plane | ✓ chiral (Δ/Λ) |

🗺️ Why cis-[M(AA)2X2][M(AA)_2 X_2] is Chiral

Two cis Cl⁻ ligands occupy adjacent positions; the two oxalate ligands wrap diagonally around the metal. The resulting structure has only a C2C_2 axis (passing through the midpoints of Cl-Cl and one oxalate). No mirror planes → chiral.

🗺️ Why trans Isomer is Achiral

In trans-[CrCl2(ox)2]3[\mathrm{CrCl_2(ox)_2}]^{3-}, the two Cl⁻ are at axial positions (180° apart). The two oxalates lie in the equatorial plane and are related by a σh\sigma_h mirror plane. → achiral.

Cis-Trans Chirality Quick Test

| Geometry | Chiral? | |---|---| | cis-[M(AA)2X2][M(AA)_2 X_2] | ✓ (Δ/Λ) | | trans-[M(AA)2X2][M(AA)_2 X_2] | ✗ | | cis-[MA2B4][M A_2 B_4] (mono only) | ✗ | | [M(AA)3][M(AA)_3] | ✓ |

⚠️ Identical Mono-Ligands ≠ Chiral

[Fe(NH3)2(CN)4][\mathrm{Fe(NH_3)_2(CN)_4}]^- has only mono-ligands. Cis or trans, mirror symmetry exists in both — neither is chiral.

Answer: (4) cis-[CrCl2(ox)2]3\boxed{\text{Answer: (4) cis-}[\mathrm{CrCl_2(ox)_2}]^{3-}}

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