JEE Main · 2023mediumCORD-021

The IUPAC name of K3[Co(C2O4)3] is:

Coordination Compounds · Class 12 · JEE Main Previous Year Question

Question

The IUPAC name of K3[Co(C2O4)3]\mathrm{K_3[Co(C_2O_4)_3]} is:

Options
  1. a

    Potassium tris(oxalato)cobaltate(III)

  2. b

    Potassium tris(oxalato)cobalt(III)

  3. c

    Potassium trioxalatocobalt(III)

  4. d

    Potassium trioxalatocobaltate(III)

Correct Answerd

Potassium trioxalatocobaltate(III)

Detailed Solution

🧠 The "-ate" Trigger

When the complex ion sits inside the brackets and bears a negative charge, the metal name flips to its anionic suffix. For Co, that's "cobaltate". For Fe, "ferrate". For Cu, "cuprate". For Ni, "nickelate". This metal-name change is the single most-tested fact in IUPAC anionic-naming questions.

🗺️ Construct the Name

The compound is K3[Co(C2O4)3]\mathrm{K_3[Co(C_2O_4)_3]} — three potassium cations and one [Co(C2O4)3]3[\mathrm{Co(C_2O_4)_3}]^{3-} anion.

Ligands. 3 × oxalato. "Oxalato" is treated as a simple ligand name in NEET/JEE convention, so we use "trioxalato", not "tris(oxalato)".

Metal & oxidation state. Bracket charge =3= -3. x+3(2)=3x=+3x + 3(-2) = -3 \Rightarrow x = +3. Anion → cobaltate(III).

Cation. Potassium (no multiplier).

Stitched: Potassium trioxalatocobaltate(III).

"Cobaltate" Wins Over "Cobalt"

If the central metal sits in an anion (square brackets carry net negative charge), the metal always takes the -ate suffix. Quick filter: any option that says "...cobalt(III)" instead of "cobaltate(III)" is wrong by definition.

⚠️ Tris(oxalato) vs Trioxalato

Some textbook variants prefer "tris(oxalato)" because oxalato itself is a substituted ligand name. JEE accepts the simpler "trioxalato" form — and that's what this question's keyed answer uses. Read the options carefully and pick the one that matches the keyed convention.

Answer: (4) Potassium trioxalatocobaltate(III)\boxed{\text{Answer: (4) Potassium trioxalatocobaltate(III)}}

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The IUPAC name of K3[Co(C2O4)3] is: (JEE Main 2023) | Canvas Classes