The number of isomers possible for [Pt(en)(NO2)2] is:
Coordination Compounds · Class 12 · JEE Main Previous Year Question
The number of isomers possible for is:
- a
2
- b
4
- c
1
- d✓
3
3
🧠 Pt(en)(NO₂)₂ — Geometry First
: Pt(II) is d⁸ → square planar. Ligands: 1 en (bidentate, occupies adjacent positions) + 2 NO₂ (ambidentate).
In square planar with bidentate en, the two NO₂ are forced cis to each other (the only available positions).
🗺️ Linkage Isomerism of NO₂
NO₂⁻ is ambidentate: bonds via N (nitro, ) or O (nitrito, ).
For 2 NO₂ ligands, the linkage combinations are:
- Both N-bonded:
- Both O-bonded:
- Mixed: (only one mixed combination — the two NO₂ positions are equivalent by the en C₂ axis)
→ 3 isomers.
🗺️ Geometric Isomerism Check
In sq pl with en: the two NO₂ must be cis. No trans option. So no geometric isomers. Only linkage isomers.
⚡ Counting Linkage Isomers
For ambidentate ligands, naive count = , but symmetry-equivalent positions reduce this. With en's axis swapping the two NO₂ positions, NN ≡ NN, OO ≡ OO, NO ≡ ON → 3 distinct.
⚠️ Pt(II) Always Square Planar
Pt(II) d⁸ is rigorously sq pl regardless of ligand strength — strong CFSE preference. No tetrahedral Pt(II).
Practice this question with progress tracking
Want timed practice with adaptive difficulty? Solve this question (and hundreds more from Coordination Compounds) inside The Crucible, our adaptive practice platform.
More JEE Main Coordination Compounds PYQs
An octahedral complex having molecular composition Co.5NH3.ClSO4 has two isomers A and B. The solution of A gives a white precipitate with AgNO3 solution and the solution of B gives white precipitate…
Number of stereoisomers possible for the complexes, [CrCl3(py)3] and [CrCl3(ox)2]3- are respectively (py = pyridine, ox = oxalate)
Given below are two statements: Statement I: A homoleptic octahedral complex, formed using monodentate ligands, will not show stereoisomerism. Statement II: cis- and trans- platin are heteroleptic…
Given below are two statements: Assertion (A): The total number of geometrical isomers shown by [Co(en)2Cl2]+ complex ion is three. Reason (R): [Co(en)2Cl2]+ complex ion has an octahedral geometry.…
Which of the following complex has a possibility to exist as meridional isomer?