The number of possible optical isomers for the complexes MA₂B₂ with sp³ and dsp² hybridized metal atom, respectively,…

🧠 Both Geometries Have Mirror Planes

$MA_2 B_2$ with sp³ hybridization → tetrahedral. With dsp² → square planar. Neither has chiral ligand environments.

🗺️ Tetrahedral $MA_2B_2$

In Td $MA_2B_2$, the molecule has a $\sigma_v$ plane (containing M, the two A ligands, and bisecting the two B ligands) → achiral, no optical isomers.

🗺️ Square Planar $MA_2B_2$

In sq pl $MA_2B_2$:

• cis form has a $\sigma_v$ plane (through the two A ligands) → achiral.
• trans form has a $\sigma_h$ plane → achiral.

Both have mirror planes → no optical isomers.

🗺️ Answer: 0 and 0

Both sp³ and dsp² $MA_2 B_2$ have 0 optical isomers.

⚡ When Does $MA_2B_2$ Get Chiral?

Only if A and/or B is itself chiral, or if multidentate ligands with specific geometries are present. Pure unidentate $MA_2B_2$ in either Td or sq pl is always achiral.

⚠️ Tetrahedral Chirality Only With 4 Different Ligands

Td $[MABCD]$ (all 4 ligands different) is chiral. $MA_2B_2$ (only 2 unique ligand types, 2 each) has $\sigma_v$ symmetry → achiral.

$\boxed{\text{Answer: (3) 0 and 0}}$